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Anit [1.1K]
3 years ago
6

[(e^x -e^-x)/(e^x + e^-x)] = 1/3​

Mathematics
1 answer:
mr_godi [17]3 years ago
5 0

Answer:

x ≈ 0.34657359

Step-by-step explanation:

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The answer would be b!

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Write an equation of the line in slope-intercept form.<br> (sorry it's blurry)
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Factor the expression completely. (If the expression is not factorable using integers, enter PRIME.)
Archy [21]
First you have to put like terms together:
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Now you factor even further. By putting what is in parentheses by what is outside the parentheses:
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What you got is correct as mine is too. I hope this formula helps for future problems:
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3 years ago
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First determine the missing angle for triangle 1 and triangle 2. Then apply the angle-angle criterion to determine if the two tr
barxatty [35]

Answer:

  • Triangle 1 – ∠1 = 25°, ∠2 = 115° Triangle 2 – ∠1 = 25°, ∠3 = 40°
  • Triangle 1 – ∠1 = 5°, ∠2 = 15° Triangle 2 – ∠2 = 15°, ∠3 = 160°

Step-by-step explanation:

You can save yourself some trouble if you realize that one of the angles in one pair must match one of the angles in the other pair.

This observation eliminates the first two choices.

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Going further, the triangles will be similar if the dissimilar angles together with one of the similar angles totals 180°.

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Triangle 1 – ∠1 = 50°, ∠2 = 30°

Triangle 2 – ∠2 = 20°, ∠3 = 100°  . . . . . no angles match

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Triangle 1 – ∠1 = 60°, ∠2 = 20°

Triangle 2 – ∠1 = 40°, ∠3 = 100°  . . . . . no angles match

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Triangle 1 – ∠1 = 25°, ∠2 = 115°

Triangle 2 – ∠1 = 25°, ∠3 = 40° . . . . 25° angles match; 25+40+115 = 180

These triangles are similar.

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Triangle 1 – ∠1 = 5°, ∠2 = 15°

Triangle 2 – ∠2 = 15°, ∠3 = 160° . . . . 15° angles match; 15+5+160 = 180

These triangles are similar.

7 0
2 years ago
Please help and i’ll mark you brainliest
Aleonysh [2.5K]

idk how to help you sorry :(

3 0
3 years ago
Read 2 more answers
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