Answer:
Explanation:
The table that shows the pattern for this question is:
Time (year) Population
0 40
1 62
2 96
3 149
4 231
A growing exponentially pattern may be modeled by a function of the form P(x) = P₀(r)ˣ.
Where P₀ represents the initial population (year = 0), r represents the multiplicative growing rate, and P(x0 represents the population at the year x.
Thus you must find both P₀ and r.
<u>1) P₀ </u>
Using the first term of the sequence (0, 40) you get:
P(0) = 40 = P₀ (r)⁰ = P₀ (1) = P₀
Then, P₀ = 40
<u> 2) r</u>
Take two consecutive terms of the sequence:
- P(1) / P(0) = 40r / 40 = 62/40
You can verify that, for any other two consecutive terms you get the same result: 96/62 ≈ 149/96 ≈ 231/149 ≈ 1.55
<u>3) Model</u>
Thus, your model is P(x) = 40(1.55)ˣ
<u> 4) Population of moose after 12 years</u>
- P(12) = 40 (1.55)¹² ≈ 7,692.019 ≈ 7,692, which is round to the nearest whole number.
Answer:
-8 and 7
Step-by-step explanation:
-8×7=-56 and -8+7=-1
Answer:
The points which satisfy the given lines is ( 1 , 1 )
Step-by-step explanation:
Given as :
The equation of lines is
y = 3 x - 2 ........ 1 And
y = - 2 x + 3 ........ 2
From equation given
3 x - 2 = - 2 x + 3
Or , 3 x + 2 x = 3 +2
Or, 5 x = 5
So , x = 
= 1
Put the value of x in eq 1
So, y = 3 ( 1 ) - 2
Or, y = 3 - 2 = 1
∴, the points ( x , y ) = ( 1 , 1 )
Hence The points which satisfy the given lines is ( 1 , 1 ) Answer
Answer:
The cheapest is the Kenyan tea which costs £1.05 for each 100g.
Step-by-step explanation:
A)
200 g of Kenyan tea costs £2.10
1. Calculate the rate of each gram, by dividing 2.10/200
0.0105 x 100 = £1.05 for each 100g
300 g of Columbian tea costs £3.45
1. Calculate the rate of each gram, by dividing 3.45/300
0.0115 x 100 = £1.15 for each 100g
1. Calculate the rate of each gram, by dividing 1.70/150
150 g of Indian tea costs £1.70
0.01133333333 x 100 = £1.133333333 for each 100g
B) The cheapest is the Kenyan tea which costs £1.05 for each 100g.
