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torisob [31]
3 years ago
15

The minimum point on the curve Y=X square - 6x + 5

Mathematics
1 answer:
Sauron [17]3 years ago
7 0

Answer:

A 20 and 45

Step-by-step explanation:

son20 & father45

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The acceleration of an object (in m/s^2) is given by the function a(t) = 9 sin(t). The initial velocity of the object is v(0) =
pentagon [3]

a) Acceleration is the derivative of velocity. By the fundamental theorem of calculus,

v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du

so that

v(t)=\left(-11\frac{\rm m}{\rm s}\right)+\int_0^t9\sin u\,\mathrm du

\boxed{v(t)=-\left(2+9\cos t)\right)\frac{\rm m}{\rm s}}

b) We get the displacement by integrating the velocity function like above. Assume the object starts at the origin, so that its initial position is s(0)=0\,\mathrm m. Then its displacement over the time interval [0, 3] is

s(0)+\displaystyle\int_0^3v(t)\,\mathrm dt=-\int_0^3(2+9\cos t)\,\mathrm dt=\boxed{-6-9\sin3}

c) The total distance traveled is the integral of the absolute value of the velocity function:

s(0)+\displaystyle\int_0^3|v(t)|\,\mathrm dt

v(t) for 0\le t and v(t)\ge0 for \cos^{-1}\left(-\frac29\right)\le t\le3, so we split the integral into two as

\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}-v(t)\,\mathrm dt+\int_{\cos^{-1}\left(-\frac29\right)}^3v(t)\,\mathrm dt

=\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}(2+9\cos t)\,\mathrm dt-\int_{\cos^{-1}\left(-\frac29\right)}^3(2+9\cos t)\,\mathrm dt

\displaystyle=\boxed{2\sqrt{77}-6+4\cos^{-1}\left(-\frac29\right)-9\sin3}

4 0
3 years ago
How are rigid transformations used to justify the SAS congruence theorem?
Katena32 [7]
(Refer to the diagram in the attached photo.)

In this diagram there is defined two Sides and an Angle in between (SAS).

Notice how there are two loose endpoints in the diagram. A single line segment can be drawn connecting the endpoints, forming a unique triangle.

If the original diagram is transformed, the dimensions and angles formed by the third line segment remains the same relative to the first two.

Therefore, if two triangles have the same SAS configuration, then they are congruent.

3 0
3 years ago
Read 2 more answers
What is the area of 4 1/5 and 1 4/9 as a mixed number.
marusya05 [52]

Answer:

10 1/9

Step-by-step explanation:

To make it easier to answer, make both of them into an improper fraction

4 1/5 = 21/3

1 4/9 = 13/9

Now we can multiply them easier

21/3 x 13/9 = 273/27

27 goes into 273 10 times and the left over is 3 so the mixed fraction would be

10 3/27, to simplify

10 1/9

5 0
3 years ago
If Emily buys a bag of food and toys for her bunny and she buys o bag of food for 20 dollars and she buys 2 toys for 3 dollars e
sasho [114]

Answer:

23

Step-by-step explanation:


7 0
3 years ago
2)<br> 2r+8-r=-7 solve the equation
Rufina [12.5K]

Answer:

r = -15

Step-by-step explanation:

2r + 8 - r = -7

~Combine like terms

r + 8 = -7

~Subtract 8 to both sides

r = -15

Best of Luck!

3 0
3 years ago
Read 2 more answers
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