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MAVERICK [17]
3 years ago
14

Cx+b=3(x-c) solve for x

Mathematics
2 answers:
lys-0071 [83]3 years ago
7 0
<span>Step 1: cx+b=3(x-c) 

</span><span><span>Step 2 :cx+b=3x−3c</span><span> 

</span><span><span>Step 3: b=3x−3c−cx
</span>
<span><span>Step 4: b+3c=3x−cx
</span>
<span><span>Step 5: b+3c=x(3−c)
</span>
<span>Step 6: x=<span><span>​<span>3−c /</span></span>​<span>​ <span>b+3c</span></span><span>​​ 
</span>

</span></span></span></span></span></span>
Dafna11 [192]3 years ago
5 0
I hope this helps you

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What is the answer to this solution. -7r−4≥ 4r+2
tia_tia [17]

Answer:

The solution is:

-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}

Please check the attached line graph below.

Step-by-step explanation:

Given the expression

-7r-4\ge \:4r+2

Add 4 to both sides

-7r-4+4\ge \:4r+2+4

Simplify

-7r\ge \:4r+6

Subtract 4r from both sides

-7r-4r\ge \:4r+6-4r

Simplify

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Multiply both sides by -1 (reverses the inequality)

\left(-11r\right)\left(-1\right)\le \:6\left(-1\right)

Simplify

11r\le \:-6

Divide both sides by 11

\frac{11r}{11}\le \frac{-6}{11}

Simplify

r\le \:-\frac{6}{11}

Therefore, the solution is:

-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}

Please check the attached line graph below.

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a grocery store sells and imported specialty cheesecake for $11 and its own store baked cheesecake for five Use the distributive
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I think its 17 the answer

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rodikova [14]

Answer:

9 as a decimal is .09

300 as a decimal is 3.0

Step-by-step explanation:

6 0
4 years ago
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