Answer:
12a cm2
2b cm2
(6a + b) cm2
Step-by-step explanation:
The complete question is
The figure consists of 12 congruent equilateral triangles. The area of one equilateral triangle is a cm2. The area of the hexagon, shaded slightly darker, is b cm2.
Which expressions represent the area of the entire shaded region, including the light and dark shading? Check all that apply.
12a cm2
2b cm2
(6a - b) cm2
(12a + 2b) cm2
(6a + b) cm2
The picture of the question in the attached figure
we know that
The area of the entire shaded region is equal to the area of the the light and dark shading
so
step 1
Find the area of the light shading
The area is equal to the area of six congruent equilateral triangles
step 2
Find the area of the dark shading
The area is equal to the area of the regular hexagon
step 3
1) Find the total area
2) Remember that the figure consists of 12 congruent equilateral triangles
so
3) The area of the light shading is the same that the area of the dark shading
so
6a=b
therefore
Sounds as tho' there were one or more illustrations with this problem. Could you possibly share the wealth?
If Triangle 1 has hyp 72 mm and one of the acute angles has measure alpha=52 deg., then the measure of the other acute angle must be (90-52), or 38 degrees.
We may now use the Law of Sines as a tool for calculating the lengths of the shorter sides alpha and beta:
a b c
----------- = ------------ = ----------------
sin alpha sin beta sin 90 deg.
Here,
c is the length of the hypo and is 72 mm;
Therefore
72 mm a
---------------- = ---------------- applies to the given data.
sin 90 deg sin 52 deg
(72 mm)(sin 52) = a(sin 90) = 1, so
(72 mm)(sin 52)
---------------------- = a = 56.74 degrees
1
and since the sum of the interior angles of the triangle must be 180, b = 180 - 56.74 deg., or beta = 33.26 deg.
Remember, . Therefore, the answer is , which is .
A number to a negative power is the reciprocal of the number (.
The correct answer is B.
- the current possible number of plates
after adding 2 letters into the 1st set:
after adding 2 letters into the 2nd set:
after adding 2 letters into the 3rd set:
after adding 1 letter into the 1st set and 1 into the 2nd set:
after adding 1 letter into the 1st set and 1 into the 3rd set:
after adding 1 letter into the 2nd set and 1 into the 3rd set:
<span>The largest possible number of plates after adding two numbers is 100.
So, </span><span>the largest possible number of additional plates is 100-60=
40</span>