48
1st seat 6 possible for each 6 only 1 possible(spouse) for seat 2
3rd seat 4 possible for each 4 only 1 possible(spouse) for seat 4
5th seat 2 possible for each 2 only 1 possible(spouse) for seat 6
6 x 4 x 2 = 48
OR 3 couples possible arrangements 3 x 2 x1 = 6
each couple 2 possible 2 x 2 x 2 = 8
therefore 6 x 8 = 48
You can exploit the difference-of-squares identity,
<em>a</em>² - <em>b</em>² = (<em>a</em> - <em>b</em>) (<em>a</em> + <em>b</em>)
Then
101.5² - 100.5² = (101.5 - 100.5) * (101.5 + 100.5)
101.5² - 100.5² = 1 * 202
101.5² - 100.5² = 202
3.4% in decimal form is .034 = r
2014 - 2004 = 10 years = t
A = 45,000(1+.034)^10
A= 62,866
Answer:
7
Step-by-step explanation:
Its 7 because khan academy and i know it
Answer:
The passing score is 645.2
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

If the board wants to set the passing score so that only the best 10% of all applicants pass, what is the passing score?
This is the value of X when Z has a pvalue of 1-0.1 = 0.9. So it is X when Z = 1.28.




The passing score is 645.2