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3 years ago

6n+7-2n-14=5n+1 asap pls

1 answer:

8 0

First, combine like terms to get 4n-7=5n+1

add 7 to both sides to get 4n=5n+8

subtract 5n from both sides to get -n=8

multiply both sides by -1 to get an answer of n=-8

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Michaela walked 2/5 mile to the store in 1/4 hour. What is her walking pace?

rusak2 [61]

Her walking pace is:
$\frac{8}{5}$

Solution

$\frac{2}{5} \div \frac{1}{4 } \\ \frac{2}{5} \times \frac{4}{1} = \frac{8}{5}$

8 0

4 years ago

Read 2 more answers

In the bin there is a 45% chance of randomly selecting ripe avocados. If you are picking avocados from the bin, you keep inspect

Archy [21]

Answer:

0.6125

Step-by-step explanation:

We have,

P(ripe avocados) = 0.45 , n = 5

by binomial distribution,

P(x=k) = ${\overset{n}C}_k P^k(1-P)^{n-k}$

P(2 ≤ x ≤ 3) = P(x=2) + P(x=3)

P(x=2) = ${\overset{5}C}_2(0.45)^2(0.55)^3$

= 10 x (0.45)² x (0.55)³

= 0.3369

P(x=3) = ${\overset{5}C}_3(0.45)^3(0.55)^2$

= 10 x (0.45)³ x (0.55)²

= 0.2756

So, P(2 ≤ x ≤ 3 ) = 0.3369 + 0.2756

= 0.6125

7 0

3 years ago

What are the lengths of the other two sides of the

damaskus [11]

Answer:

D) AC = 5 and BC = 53

Step-by-step explanation:

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3 years ago

Molecules of a toxic chemical eventually decompose into inert substances. Suppose the decomposition time is exponentially distri

koban [17]

Answer:

a) 4.16 years

b) 27.73 years

c) 238.44 years

d) 3,870.53 years

Step-by-step explanation:

Let X be the random variable that measures the decomposition time.

$\bf \lambda =6$

In this case, since the decomposition time is exponentially distributed with a mean of 1/6, we have

$\bf P(X\leq t)=1-e^{-t/6}\Rightarrow P(X>t)=1-(1-e^{-t/6})=e^{-t/6}$

and we must find a t such that P(x>t)=0.5.

$\bf P(X>t)=0.5\Rightarrow e^{-t/6}=0.5\Rightarrow -t/6=ln(0.5)\Rightarrow t=-6ln(0.5)=4.16\;years$

$\bf \lambda =40$

$\bf P(X>t)=0.5\Rightarrow e^{-t/40}=0.5\Rightarrow -t/40=ln(0.5)\Rightarrow t=-40ln(0.5)=27.73\;years$

$\bf \lambda =344$

$\bf P(X>t)=0.5\Rightarrow e^{-t/344}=0.5\Rightarrow -t/344=ln(0.5)\Rightarrow t=-344ln(0.5)=238.44\;years$

$\bf \lambda =5584$

$\bf P(X>t)=0.5\Rightarrow e^{-t/5584}=0.5\Rightarrow -t/5584=ln(0.5)\Rightarrow t=-5584ln(0.5)=3870.53\;years$

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3 years ago

Story Problem

LenKa [72]

14.95 would be the answer

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3 years ago