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White raven [17]
3 years ago
13

How do you determine what could represent a function in algebra

Mathematics
2 answers:
n200080 [17]3 years ago
7 0
Hi, here is my answer:
First, if you want to determine that's relation is function, you have to realize that your value of x(Domain) is not repeated.= so, it's a function
But...If your value of x (Domain) is repeated twice or more, so I can guaranteed that is totally NOT a function

alisha [4.7K]3 years ago
4 0
Hi there! To answer your question or more questions like these you'd want to determine that relation is function, the value of x which would be your base or domain is not repeated, so by using this guideline you can determine if it's a function. On the other hand, if your value of x is repeated twice or more (+), it isn't a function. Hope this helps you and remember to mark as brainliest! BTW I like the question. It made me think a lot. :)
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3 years ago
Please help me Simplify: 6! − 3!
djverab [1.8K]

Answer: Option B 3!((6×5×4)-1)

Step-by-step explanation:

6! - 3!

= (1×2×3×4×5×6) - (1×2×3)

= 720 - 6

= 714

As you told you forgot to put options lemme answer it.

It will be option B

3!((6×5×4)-1)

It will be 6((6×5×4)-1)

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= 720 - 6

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please click thanks and mark brainliest if you like :)

5 0
3 years ago
Read 2 more answers
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Zinaida [17]

Answer:

x = 6

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Step-by-step explanation:

Plug y into the first equation.

5x - 7(-x+2) = 58

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8 0
3 years ago
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tomas wrote an equation 4/5x-8=. Finish the equation so that the equation will have no solution. Explain how you know.
Pepsi [2]

Answer:

Right part: \dfrac{4}{5}x+a, where a\neq -8.

Step-by-step explanation:

Linear equation have no solution if it is impossible for the equation to be true no matter what value we assign to the variable x.

The left part of the equation Tomas wrote is

\dfrac{4}{5}x-8.

The right part of the equation should be of the form

\dfrac{4}{5}x+a,

where a\neq -8.

In this case, the equation will take look

\dfrac{4}{5}x-8=\dfrac{4}{5}x+a,\\ \\-8=a.

Since a\neq -8, this equality is always false.

Remark: 1) If a=8, the equation \dfrac{4}{5}x-8=\dfrac{4}{5}x+a is equivalent to the equation

\dfrac{4}{5}x-8=\dfrac{4}{5}x-8,\\ \\0=0

and the lest equation has infinitely many solutions.

2) When coefficient at x differs from \dfrac{4}{5}, the equation has unique solution.

6 0
3 years ago
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