All categories

3 years ago

When two objects are near each other, how would increasing one object’s mass affect it?

1 answer:

5 0

When two objects are near each other, increasing one object's mass would cause the gravitational force of the object to increase. where m and M are the masses of the two objects, d is the distance between their centres, and G is the gravitational constant.

You might be interested in

What is the distance around a triangle that has sides measuring 2/18 feet 3/12 feet and 2/12 feet

Minchanka [31]

The distance around an object is called the perimeter. To get the perimeter, you add up the sides. So, 2/18 + 3/12 + 2/12 = your answer.

4 0

2 years ago

If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle

stira [4]

Answer:

The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²

 or 

The equation of the circle x² + 2 x + y² - 4 y = 15

Step-by-step explanation:

Given points end Points are p(-3,-2) and q( 1,6)

The distance of two points formula

P Q = $\sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2} }$

P Q = $\sqrt{1 - (-3)^{2} + ((6 -(-2))^{2} }$

P Q = $\sqrt{16+64} = \sqrt{80}$

The diameter 'd' = 2 r

2 r = √80

= $\sqrt{16 X 5}$

= $4 \sqrt{5}$

r = 2√5

Mid-point of two end points

$(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )$

= (-1 ,2)

Mid-point of two end points = center of the circle

(h,k) = (-1 , 2)

The equation of the circle

(x -h )² +(y-k)² = r²

(x -(-1) )² +(y-(2))² = (2(√5))²

x² + 2 x + 1 + y² - 4 y + 4 = 20

x² + 2 x + y² - 4 y = 20 -5

x² + 2 x + y² - 4 y = 15

Final answer:-

The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²

 or 

The equation of the circle x² + 2 x + y² - 4 y = 15

6 0

3 years ago

Which is the equation of the graphed line written in standard form? y = x x – 1/2y = 0 x – y = 0 y =1/2x

Airida [17]

The standard for of this equation is x – y = 0

Firstly, options A and D are not in standard form, so they are not options.

To decided between B and C, we choose a point on the line and see if it works. For example, we'll use (2, 2).

x – y = 0

2 - 2 = 0

0 = 0

This is true for option C. Therefore, it is correct.

4 0

2 years ago

Comparing Rainfalls

BlackZzzverrR [31]

Answer:

4mm

Step-by-step explanation:

It worked for me

3 0

2 years ago

Read 2 more answers

Please help me :(

valina [46]

Answer:

The limits between which T lies is 273 hours 30 mins < T < 242 hours 30 minutes

Step-by-step explanation:

The number of hours Angharad sleeps each night = 8 hours ± 10 minutes

The actual time Angharad sleeps each night = 8 hours ± 5 minutes

Which gives the maximum time Angharad sleeps = 8 hours 5 minutes = 485 minutes per night

The minimum time Angharad sleeps = 7 hours 55 minutes = 475 minutes

The number of days in the month of November = 30 nights

The maximum time in minutes Angharad sleeps in November, $T_{max}$ = 30 nights × 485 minutes/night = 14,550 minutes = 242.5 hours = 242 hours 30 minutes

The minimum time in minutes Angharad sleeps in November, $T_{min}$ = 30 nights × 475 minutes/night = 14,250 minutes = 237.5 hours = 237 hours 30 minutes

Therefore, we have, the limits between which T lies given as follows;

273.5 hours < T < 242.5 hours.

8 0

2 years ago

Read 2 more answers