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algol [13]
3 years ago
10

The measure of central angle XYZ is 3(3.14)/4 radians.

Mathematics
1 answer:
lana [24]3 years ago
8 0

Answer: 96 units 2

sorry i cant post this if i dont have more then 20 characters

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To complete her holiday wrapping Bella needs identical strips of ribbon measuring 3.5 feet each she has 85 feet of ribbon in tot
Anon25 [30]

Answer:

She can cut 24 ribbon from this long strip.

Step-by-step explanation:

Given that,

Bella needs identical strips of ribbon measuring 3.5 feet each.

She has 85 feet of ribbon.

3.5 feet is length of 1 ribbon.

1    feet is length of \frac{1}{3.5} ribbon

85 feet is length of \frac{1\times 85}{3.5} ribbon

                              ≈24.28

\frac{85}{3.5}=\frac{85\times10}{35}=\frac{85\times2}{7}=\frac{170}{7}

7) 170(24

   14

_______

     30

     28

  ______

        2

So, she can cut 24 ribbon from this long strip.

5 0
3 years ago
What is the area of the circle if XY = 5.4 mm? 5.4π mm2 7.29π mm2 10.8π mm2 14.58π mm2
Dafna1 [17]

Answer: 7.29π mm²

Step-by-step explanation:

First, I am assuming XY is the diameter of the circle :)

The formula for the area of a circle is πr² (r = radius)

So that means we need to divide the diameter by 2 to find the radius

5.4 / 2 = 2.7

Now we simply plug in our numbers!

3.14 · 2.7²

3.14 · 7.29

And that's it!

Hope this helped you :)

3 0
4 years ago
Determine if the ordered pair is a solution of the equation.
lakkis [162]
A. True
y=3x
3=3(1)
3=3
7 0
3 years ago
Which of the following describes a compound event?
wariber [46]

Answer:

the answer would be A.

Step-by-step explanation:

it would be that answer because to or more simple things are more likely to happen. like tossing 5 coins and getting 4 heads . SIMPLE.

6 0
3 years ago
f 20% of the population are homozygous for the scalp-wiggling allele •(qq, or q 2), then what proportion of the population is ho
11Alexandr11 [23.1K]

Answer:

The proportion of the population that is homozygous for the non-wiggling allele is 0.3056.

Step-by-step explanation:

Denote the variables as follows:

<em>q²</em> = number of people who are homozygous for the scalp-wiggling allele.

<em>p²</em> = number of people who are homozygous for the non-wiggling allele.

It is provided that the proportion of the population who are homozygous for the scalp-wiggling allele is, <em>q²</em> = 0.20.

Compute the value of <em>q</em> as follows:

q^{2}=0.20\\q=\sqrt{0.20}\\=0.4472

Compute the value of <em>p</em> as follows:

p=1-q\\=1-0.4472\\=0.5528

Compute the proportion of the population who are homozygous for the non-wiggling allele as follows:

p^{2}=(0.5528)^{2}=0.30558784\approx0.3056

Thus, the proportion of the population that is homozygous for the non-wiggling allele is 0.3056.

7 0
3 years ago
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