0^9 +7x+189yx−3y
o
9
+7x−3y
9
+7x+3y
9
−7x−3y
9
−7x+3y
9
+7x+189yx−3y
2 Collect like terms.
{o}^{9}+(7x+7x-7x-7x+7x)+(-3{y}^{9}+3{y}^{9}-3{y}^{9}+3{y}^{9})+189yx-3y
o
9
+(7x+7x−7x−7x+7x)+(−3y
9
+3y
9
−3y
9
+3y
9
)+189yx−3y
3 Simplify.
{o}^{9}+7x+189yx-3y
o
9
+7x+189yx−3y
Step 1: Factor out variable m.<span><span>m<span>(<span><span>−<span>50n</span></span>+35</span>)</span></span>=<span>3p</span></span>Step 2: Divide both sides by -50n+35.<span><span><span>m<span>(<span><span>−<span>50n</span></span>+35</span>)</span></span><span><span>−<span>50n</span></span>+35</span></span>=<span><span>3p</span><span><span>−<span>50n</span></span>+35</span></span></span><span>m=<span><span>3p</span><span><span>−<span>50n</span></span>+35</span></span></span>Answer:<span>m=<span><span><span>3p</span><span><span>−<span>50n</span></span>+35</span></span></span></span>
For the answer to the question above, If you've noticed, the statement mentioned "a number". Let's assign x to be the number. The first statement is twice a number (2x). Then, decreased by the quotient of that number and 2 (-x/2). Lastly, the statement at least 12 is written as >12.
So the answer is
2x - (x/2) >12
A. 100/20
The distance in meters should be divided by the time in seconds to get the value of the distance in meters travelled in one second.
