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3 years ago

10

Solve 18x 6 = 3(6x 1)

1 answer:

Artemon [7]3 years ago

5 0

18x+6=3(6x+1)
18x-18x=3-6
0x=-3

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What is square root 10 over square root 3 in simplest radical form

Sergio039 [100]

I'll give you a few examples of a square root over a square root first, so you'll understand how I got the answer:

1. √a / √b = √ab / b
2. √2 / √3 = √2*3 / 3 = √6 / 3
3. 1 / √a = √a / a
4. √3 / √7 = √21 / 7

I think you get how it works now.

Now lets solve the question.

√10 / √3
can also be written as √10 * 1/√3
1/√3 simplified is √3/3
So, √10 / √3 = √10 * √3/3
= √10*√3 / 3
= √30 / 3
Factor 30 (2*3*5) and make sure there are no pairs of factors that are the same. (for example: two 2's or two 4's)
If there are any pairs of factors, then take them outside the square root.
ex: √20 = √2*2*5 = 2√5

That was the long way to solve it, but there is a trick:
Remember what √a / √b equals?
It equals √a*b / b.
This means √10 / √3 is simply just √30 / 3.
Then all you need to do is make sure the number inside the radical has no pairs of factors then you are good to go.

4 0

3 years ago

Complete the point-slope equation of the line through (2,3) and (7,4) <br> y-4=

Anna71 [15]

Answer:

y - 4 = $\frac{1}{5}$ (x - 7)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (2, 3) and (x₂, y₂ ) = (7, 4)

m = $\frac{4-3}{7-2}$ = $\frac{1}{5}$

Use either of the 2 points for (a, b)

Using (7, 4), then

y - 4 = $\frac{1}{5}$ (x - 7) ← in point- slope form

4 0

3 years ago

Jimmy wants to buy socks that cost $20 how much change does he receive if he gives the cashier $100?

max2010maxim [7]

80 dollars is what jimmy would get back

7 0

3 years ago

Find a number which decreased by 10 is 4 times its opposites.

Katena32 [7]

Answer:

40

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

I need answer Immediately pls!!!!!!

Illusion [34]

Given:

Total number of students = 27

Students who play basketball = 7

Student who play baseball = 18

Students who play neither sports = 7

To find:

The probability the student chosen at randomly from the class plays both basketball and base ball.

Solution:

Let the following events,

A : Student plays basketball

B : Student plays baseball

U : Union set or all students.

Then according to given information,

$n(U)=27$

$n(A)=7$

$n(B)=18$

$n(A'\cap B')=7$

We know that,

$n(A\cup B)=n(U)-n(A'\cap B')$

$n(A\cup B)=27-7$

$n(A\cup B)=20$

Now,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=7+18-n(A\cap B)$

$n(A\cap B)=7+18-20$

$n(A\cap B)=25-20$

$n(A\cap B)=5$

It means, the number of students who play both sports is 5.

The probability the student chosen at randomly from the class plays both basketball and base ball is

$\text{Probability}=\dfrac{\text{Number of students who play both sports}}{\text{Total number of students}}$

$\text{Probability}=\dfrac{5}{27}$

Therefore, the required probability is $\dfrac{5}{27}$ .

3 0

3 years ago