Answer:
Let the speed of the train be x km/h.
Case 1:
Distance = 288 km
Speed = x km/h
Time = Distance/Speed
= 288/x h
Case 2:
Distance = 288 km
Speed = (x+4) km/h
Time = 288/x + 4 h
Since 288/x > 288/x + 4
288/x - 288/x+4 = 1
288[1/x - 1/x+4 ] = 1
[ x + 4 - x / x(x + 4) ] = 1/288
[4 / x^2 + 4x ] = 1/288
x^2 + 4x = 1152
x^2 + 4x - 1152 = 0
x^2 + 36x - 32x - 1152 = 0
x(x + 36) - 32(x + 36) = 0
(x + 36)(x - 32) = 0
x + 36 = 0 , x - 32 = 0
x = -36 , x = 32
x = -36 , rejected since speed cannot be negative.
Therefore , speed of the train = 32 km/h
Answer: -20
Read more at Answer.Ya.Guru – https://answer-ya.com/questions/5043911-5-2-3-7-50.html
Step-by-step explanation: PEMDAS use this ok first you do 7x7 to equal 49 then add 50 to equal 99. then do 5x5x5 to equal 125. the parentheses are gone and the 5x5x5 is gone now the problem is 125-2x3-99. to finish you multiply 2x3 to equal 6 now 125-6-99=20 answer-20
Read more at Answer.Ya.Guru – https://answer-ya.com/questions/5043911-5-2-3-7-50.html
It is 8/5. Hope this helps :)
4squared 3, 3/4 is what I got
You can use the fractions 3/18 and 5/12.
Hope this helps :)
