Answer:
true
Step-by-step explanation:
Answer:
Likely
Step-by-step explanation:
0.90 is also equal to 90% which is very likely to happen.
(√3 - <em>i </em>) / (√3 + <em>i</em> ) × (√3 - <em>i</em> ) / (√3 - <em>i</em> ) = (√3 - <em>i</em> )² / ((√3)² - <em>i</em> ²)
… = ((√3)² - 2√3 <em>i</em> + <em>i</em> ²) / (3 - <em>i</em> ²)
… = (3 - 2√3 <em>i</em> - 1) / (3 - (-1))
… = (2 - 2√3 <em>i</em> ) / 4
… = 1/2 - √3/2 <em>i</em>
… = √((1/2)² + (-√3/2)²) exp(<em>i</em> arctan((-√3/2)/(1/2))
… = exp(<em>i</em> arctan(-√3))
… = exp(-<em>i</em> arctan(√3))
… = exp(-<em>iπ</em>/3)
By DeMoivre's theorem,
[(√3 - <em>i </em>) / (√3 + <em>i</em> )]⁶ = exp(-6<em>iπ</em>/3) = exp(-2<em>iπ</em>) = 1
<span>1A + 2C = $24, or, since A = 2S, you can write this as
2S + 2C = $24
The difference between $17 and $24 is $7, so this must be the cost of a child's ticket. Subtract this from $17 and you get $10, which must be the cost of 2 Senior tickets. So the Senior ticket costs $5, and the Adult ticket must cost $10.
Therefore 1 Adult and 1 Senior ticket costs $15 </span><span>
</span>