The rectangular prism has a volume of 936 cubic inches. Write and solve an equation to find the missing dimension of the prism.

The expression f(x) = 12(1.035)* models the monthly growth of membership in the new drama club at a school. According to the fun

olga nikolaevna [1]

Answer:

The monthly growth rate is 3.5%.

Step-by-step explanation:

The exponential growth function is given as follows:

$y=a(1+r)^{x}$

Here,

y = final value

a = initial value

r = growth rate

x = time taken

The provided expression for the monthly growth of membership in the new drama club at a school is:

$f(x) = 12\cdot(1.035)^{x}$

Comparing this function with the exponential growth function:

$a(1+r)^{x}=12(1.035)^{x}\\\\a(1+r)^{x}=12(1+0.035)^{x}$

Then value of r is 0.035 or 3.5%.

Thus, the monthly growth rate is 3.5%.

7 0

3 years ago

PLEASE ANSWER ASAP! please

FinnZ [79.3K]

Answer:

3 ÷ 0.5

Step-by-step explanation:

Since each large square is 1 whole, and theirs five out of 10 columns that are distinctivly a different orange, it'd be 3 divided by 0.5.

5 0

2 years ago

Simplify (5^3)^6 leaving your answer in index form

Verizon [17]

$( {5}^{3} ) ^{6} = {5}^{3 \times 6} = {5}^{18}$

5 0

3 years ago

Read 2 more answers

If ΔABC ≌ ΔRPQ , ∠A = 35˚, ∠C=75˚ , Find the measure of ∠Q. *

Norma-Jean [14]

<h3>Answer: angle Q = 75 degrees</h3>

Explanation:

The order of ABC and RPQ is important so we can match up the angles like so

angle A = angle R .... first letters
angle B = angle P .... second letters
angle C = angle Q ... third letters

Meaning that angle Q = 75 since angle C is this measure.

3 0

3 years ago

Read 2 more answers

beginning at sea level a scuba diver dove 1 2/3 feet into the water , and then dove an additional 3 2/5 feet at what elevation i

skad [1K]

The given details are illustrations of addition and subtractions of fractions. The scuba driver is at an elevation of $-5\frac{1}{15}$ ft below the sea level.

Given that:

$n_1 = 1\frac 23$ --- the first dive

$n_2 = 3\frac 25$ ---- the additional dive

From the question, we understand that the diver starts at the sea level.

This is represented with 0ft.

So, the diver's elevation (d) is calculated as follows:

$d = 0 - n_1 - n_2$ --- we use subtraction because the diver is below the sea level

So, we have:

$d = 0 - 1\frac 23 - 3\frac 25$

$d = - 1\frac 23 - 3\frac 25$

Convert fractions

$d = - \frac 53 - \frac{17}5$

Take LCM

$d = \frac{-5 \times 5 - 17 \times 3}{15}$

$d = \frac{-76}{15}$

Reduce fraction

$d = -5\frac{1}{15}$

The above value means that the diver's elevation is at $-5\frac{1}{15}$ ft below the sea level.