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Sindrei [870]
3 years ago
7

Factor completely, then place the answer in the proper location on the grid. a3 - b3

Mathematics
2 answers:
kirill115 [55]3 years ago
7 0
\bf \textit{difference of cubes}
\\\\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3 
\\\\
a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad
(a-b)(a^2+ab+b^2)= a^3-b^3\\\\
-------------------------------\\\\
a^3-b^3\implies (a-b)(a^2+ab+b^2)
Effectus [21]3 years ago
7 0

Answer:

We have to find the difference of cubes of any two real numbers

a^3-b^3=(a-b)(a^2+ab+b^2)

Verification of the Result

RHS

  =(a-b)(a^2+ab+b^2)\\\\=a \times (a^2+ab+b^2)-b \times (a^2+ab+b^2)\\\\\text{Using Distributive property }\\\\=a^3+a^2b+ab^2-ba^2-ab^2-b^3\\\\ \text{Cancelling like terms}\\\\=a^3-b^3

=LHS

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Answer:

<h3>Required <u>Answer</u><u>:</u><u>-</u></h3>

\sf 4x+8y=10\dots\dots (1)

\sf -4x+2y=-30\dots\dots (2)

  • by adding eq (1) and eq (2) we get

{:}\longrightarrow\sf 4x+8y=20

{:}\longrightarrow\sf -4x+2y=-30

<h2>__________________________</h2>

{:}\longrightarrow\sf 10y=-10

{:}\longrightarrow\sf y={\dfrac {-10}{10}}

{:}\longrightarrow{\underline{\boxed{\bf y=-1}}}

  • Substitute the value in eq (2)

{:}\longrightarrow\sf -4x+2 (-1)=-30

{:}\longrightarrow\sf -4x-2=-30

{:}\longrightarrow\sf -4x=-30+2

{:}\longrightarrow\sf -4x=-28

{:}\longrightarrow\sf x={\dfrac {-28}{-4}}

{:}\longrightarrow{\underline{\boxed{\bf x=7}}}

\therefore{\underline{\boxed{\bf (x,y)=(7,-1)}}}

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