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aniked [119]
3 years ago
6

A square has a side length of 16.5 in. If the area is multiplied by 9, what happens to the side length?

Mathematics
1 answer:
nika2105 [10]3 years ago
7 0

Answer: The side length is tripled.

Step-by-step explanation: Area is length times width, or in the case of a square, s²

If the area is multiplied by 9, (that is 3²) it means the sides are 3 times as long.

16.5² = 272.25

(3)(16.5) = 49.5

49.5² = 2450.25

the same as 272.25 × 9

Triple the side length results in 9 times the area.

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It takes Ron 3 hours to paint one side of a house. It takes Natalie 6 hours to paint the same area. What is Natalie's rate
My name is Ann [436]

Answer:

the answer is 6x3 which is 18

Step-by-step explanation:multiply to find out the answer

4 0
3 years ago
The following are the number of sales which a sample of 9 car salespeople of an insurance company in Florida and a sample of 8 s
Montano1993 [528]

Answer:

There is no difference in the number of sales between The Florida salespeople and Washington salespeople

Sp^2 = 39

Step-by-step explanation:

Given data :

Florida: 39, 44, 42, 50, 55, 48, 51, 38, 54

Washington: 42, 43, 56, 50, 49, 52, 53, 56

number of sales persons in Florida = 9

number of sales persons in Washington = 8

variance = constant

a)Determine if there is difference between the Florida salespeople and Washington salespeople

we will carry out a two tailed test based on the given data

H0 : u1 = u2  

H1 : u1 ≠ u2

x ( mean ) = 46.77,  y ( mean ) = 50.13 ,

s1^2 = 39.69,  s2^2 = 28.41,   n1 = 9 ,   n2 = 8

therefore :

Sp^2 = \frac{n1s1^2 + n2s2^2}{n1 + n2-2} =  38.96  ≈ 39

performing test statistic

t = \frac{x- y }{sp\sqrt{\frac{1}{n1} +\frac{1}{n2} } }    = \frac{-3.36}{3.0330} = -1.1078

critical value is at t = 0.05 and for a two tailed test it is at 2.13  therefore e accept H0 at 5% .    This shows that there is no difference in sales

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3 years ago
Can someone help me!!!
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4 years ago
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Find a formula for the inverse of the function. f(x) = e^6x − 9
STatiana [176]

Answer:

f^{-1}(x)=\frac{1}{6}\ln(x+9)

Step-by-step explanation:

So we have the function:

f(x)=e^{6x}-9

To solve for the inverse of a function, change f(x) and x, change the f(x) to f⁻¹(x), and solve for it. Therefore:

x=e^{6f^{-1}(x)}-9

Add 9 to both sides:

x+9=e^{6f^{-1}(x)}

Take the natural log of both sides:

\ln(x+9)=\ln(e^{6f^{-1}(x)})

The right side cancels:

\ln(x+9)=6f^{-1}(x)

Divide both sides by 6:

f^{-1}(x)=\frac{1}{6}\ln(x+9)

And we're done!

7 0
3 years ago
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