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3 years ago

12

A well of diameter 4m is dug 14m deep. The earth taken out is spread evenly all around the well to form a 40cm high embankment.

Find the width of the embankment

1 answer:

dimulka [17.4K]3 years ago

8 0

Answer:

82.72m

Step-by-step explanation:

Volume = πr2h

= 3.142*7*7*14

= 2,155.41m³

Now that we hav the volume of earth, we go on to find the raduis of the spread

2155.41m³ = 3.142*r²*0.4

2155.41m³ = 1.26r²

r² = 1,710.64

r = 41.36m

Width = diameter = 2r = 82.72m

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On Sunday, a local hamburger shop sold a combined total of 428 hamburgers and cheeseburgers. The number of cheese burgers sold w

melisa1 [442]

The equation you can use is x + 3x = 428 with x as the number of cheeseburgers and 3x the number of hamburgers
you solve for x and get 4x= 428 and x=107

so 321 hamburgers were sold that day.

5 0

2 years ago

Alejandra's Tapas Bar offers a menu consisting of $9$ savory and $5$ sweet dishes. You can also get a mix-and-match plate consis

Mariana [72]

Answer:

45

Step-by-step explanation:

Given that the number of savory dishes is 9 and the number of sweet dished is 5.

Denoting all the 9 savory dishes by $p_1, p_2,...,p_9$ , and all the sweet dishes by $q_1,q_2,...,q_5$ .

The possible different mix-and-match plates consisting of two savory dishes are as follows:

There are 9 plates with $q_1$ from sweet plates which are $(q_1, p_1), (q_1, p_2), ..., (q_1,p_9).$

There are 9 plates with $q_2$ from sweet plates which are $(q_2, p_1), (q_2, p_2), ..., (q_2,p_9).$

Similarly, there are 9 plated for each $q_3, q_4$ and $q_5.$

Hence, the total number of the different mix-and-match plates consisting of two savory dishes

$= 9+9+9+9+9= 9\times5=45$

7 0

3 years ago

Select all of the following tables which represent y as a function of x.x 5 10 11y 3 9 15x 5 10 11y 3 9 9x 5 10 10y 3 9 15

11Alexandr11 [23.1K]

Answer:

Table 1 and 2 represent a function

Step-by-step explanation:

Given

<em>Table 1</em>

x 5 10 11

y 3 9 15

<em></em>

<em>Table 2</em>

x 5 10 11

y 3 9 9

<em>Table 3</em>

x 5 10 10

y 3 9 15

Required

Determine which of the tables represent that y is a function of x

For a relation to be a function; the x values must be unique.

In other words, each x value must not be repeated;

Having said that;

Analyzing Table 1

<em>Table 1</em>

x 5 10 11

y 3 9 15

<em></em>

Note that the x rows are unique as no value were repeated;

Hence, Table 1 is a function

<em>Table 2</em>

x 5 10 11

y 3 9 9

Note that the x rows are unique as no value were repeated;

Hence, Table 2 is a function

<em>Table 3</em>

x 5 10 10

y 3 9 15

Note that the x rows are not unique because 10 was repeated twice;

Hence, Table 3 is not a function

7 0

2 years ago

Your school wants to take out an ad in the paper congratulating the basketball team on a successful season, as shown to the rig

iogann1982 [59]

Answer:

$x_1 =-14.43 in, x_2 = 2.426in$

Since the measurement can't be negative the correct answer for this case would be $x =2.426 in$

Step-by-step explanation:

Let's assume that the figure attached illustrate the situation.

For this case the we know that the original area given by:

$A_i = 7 in *5 in = 35in^2$

And we know that the initial area is a half of the entire area in red $A_i = \frac{A_f}{2}$ , so then:

$A_f = 2 A_ i =2*35 = 70$

And we know that the area for a rectangular pieces is the length multiplied by the width so we have this:

$70 = (x+7) (x+5)$

We multiply both terms using algebra and the distributive property and we got:

$70 =x^2 +12 x +5$

And we can rewrite the expression like this:

$x^2 +12 x -35 = 0$

And we can solve this using the quadratic formula given by:

$x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}$

Where $a = 1, b =12 and c=-35$ if we replace we got:

$x = \frac{-12 \pm \sqrt{(12)^2 -4(1)(-35)}}{2*1}$

And the two possible solutions are then:

$x_1 =-14.43 in, x_2 = 2.426in$

Since the measurement can't be negative the correct answer for this case would be $x =2.426 in$

3 0

3 years ago

37= -3+5(x + 6) slove for x

lions [1.4K]

Step 1: Simplify both sides of the equation.
37
=
−
3
+
5
(
x
+
6
)
37
=
−
3
+
(
5
)
(
x
)
+
(
5
)
(
6
)
(Distribute)
37
=
−
3
+
5
x
+
30
37
=
(
5
x
)
+
(
−
3
+
30
)
(Combine Like Terms)
37
=
5
x
+
27
37
=
5
x
+
27
Step 2: Flip the equation.
5
x
+
27
=
37
Step 3: Subtract 27 from both sides.
5
x
+
27
−
27
=
37
−
27
5
x
=
10
Step 4: Divide both sides by 5.
5
x
5
=
10
5
x
=
2

8 0

3 years ago