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Genrish500 [490]
3 years ago
12

Andre makes a three-digit number.

Mathematics
1 answer:
s2008m [1.1K]3 years ago
8 0

Answer:  115,151,115,133,313,331

Step-by-step explanation:

The Andre's  number can consist from 1+1+5 or 3+3+1. There are no any other sets of 3 odd digit to get 7.

Lets prove this statement.

Lets 1 of the digit is bigger than 5. However the digit is odd so it can be 7 only. However in this case the residual 2 digits are 0 . This is not possible so the gigits are odd however 0 is even.

Lets check the case when the biggest digit in the set is smaller than 3.

So it can be 1 only.

So the residual 2 digits can be 1 only. The sum of 1+1+1<7 .

SO we've  prooven that the only sets of the digits are 1;1;5 or 3;3;1

The set   1;1;5 can give 3 numbers:

115,151,115

The set   1;3;3 can give 3 numbers as well:

133,313,331

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  a) ∠DAE = 33°; ∠ABD = 57°

  b) ∠CEB = 90°

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Step-by-step explanation:

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__

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__

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