Answer: 115,151,115,133,313,331
Step-by-step explanation:
The Andre's number can consist from 1+1+5 or 3+3+1. There are no any other sets of 3 odd digit to get 7.
Lets prove this statement.
Lets 1 of the digit is bigger than 5. However the digit is odd so it can be 7 only. However in this case the residual 2 digits are 0 . This is not possible so the gigits are odd however 0 is even.
Lets check the case when the biggest digit in the set is smaller than 3.
So it can be 1 only.
So the residual 2 digits can be 1 only. The sum of 1+1+1<7 .
SO we've prooven that the only sets of the digits are 1;1;5 or 3;3;1
The set 1;1;5 can give 3 numbers:
115,151,115
The set 1;3;3 can give 3 numbers as well:
133,313,331
