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wariber [46]
3 years ago
6

What is the inverse of the following statement? If it is night, the street lights will come on. Select the best answer from the

choices provided. A. If the street lights come on, then it is night. B. The street lights will come on if it is night. C. If it is not night, then the street lights will not come on. D. If the street lights do not come on, then it is not night.
Mathematics
1 answer:
marshall27 [118]3 years ago
3 0

ANSWER

C. If it is not night, then the street lights will not come on.

EXPLANATION

The given statement is

"If it is night, then the street lights will come on"

Given the statement,

"If p, then q",

then the inverse of this statement is

"If it is not night,then the street lights will not come on"

"If not p, then not q"

The correct choice is C.

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ololo11 [35]

Answer:

the first step is to subtract the 2W from each sides of the equal sides

Step-by-step explanation:

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the first step is to subtract the 2W from each sides of the equal sides

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3 years ago
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Ivenika [448]
Look at!!:
Pre image  A(3,4), B(1,5) C(6,6);
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A(3,4)              ⇒ A`(3*3/2, 4*3/2)=(4.5, 6)
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7 0
3 years ago
Which set is closed under subtractionWhich answer choice shows that the set of irrational numbers is not closed under addition
vovikov84 [41]

Answer:

(a) Set of rational numbers

(b) \pi + (-\pi) = 0

Step-by-step explanation:

Solving (a): Set that is closed under subtraction

The solution to this is rational numbers.

For a set of number to be closed under subtraction, the following condition must be true

a -b = c

Where

a, b, c are of the same set.

The above is only true for rational numbers.

e.g.

1 - 2 = -1

5 - 5 = 0

\frac{1}{2} - \frac{1}{4} = \frac{1}{2}

4 - 2 = 2

The operations and the result in the above samples are rational numbers.

Solving (b): Choice not close under addition[See attachment for options]

As stated in (a)

For a set of number to be closed under subtraction, the following condition must be true

a -b = c

Where

a, b, c are of the same set.

In the given options (a) to (d), only

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\pi is irrational while 0 is rational

<em>In other words, they belong to different set</em>

8 0
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