I'm pretty sure its x=<span><span>−79/</span><span>4
</span></span>
Answer:
(a) (a² +3a -1)(a² -3a -1)
Step-by-step explanation:
The constant term of the product of the factors will be equal to the product of their constants. Since you want that product to be +1, the signs of the factor constants must be the same. That eliminates choices (c) and (d).
__
To tell which of choices (a) and (b) is correct, we can compute the squared term in their product. Let's do it in a generic way, with the constant (±1) being represented by "c".
We want the a² term in the product ...
(a² +3a +c)(a² -3a +c)
That term will be the result of multiplying both sets of first and last terms, and adding the product of the middle terms:
(a²·c) +(a²·c) -9a² = a²(2c-9)
So, we want the factor (2c-9) to be -11, which means c=-1, not +1.
The correct factorization of the given expression is ...
(a² +3a -1)(a² -3a -1) . . . . matches choice A
Answer:
Step-by-step explanation:
Start with the circumference.
C = 2*pi*r
C = 301.5
pi = 3.14
r = ??
Solution
301.5=3.14 * 2 * r
301.5 = 6.28*r
r = 301.5/6.28
r = 48.01
So the radius = 48.01
The diameter is twice as much or 48.01 * 2 = 96.02
D= (LR_2)/(R_2+R_1)
<span>d(R_2+R_1)= LR_2 </span>
<span>d(R_2+R_1)/(R_2)= L </span>
<span>L= d(R_2+R_1)/(R_2) </span>
<span>The answer I obtained is the same answer as the third choice. </span>
<span>L= d(R_2+R_1)/(R_2) </span>
<span>L= (R_2+R_1)d/(R_2) </span>
<span>L= (R_2+R_1)(d)/(R_2) </span>
<span>L= ((R_2+R_1)(d))/(R_2)</span>
Jasmine needs 20.02 meters to make the drapes
Step-by-step explanation:
Jasmine needs 22 yards of material to make drapes, but the fabric
store sells material by the meter, we need to find how many meters
of material Jasmine needs to make the drapes
- If 1 yard equals about 0.91 meters
- Change 22 yards to meters
∵ 1 yard = 0.91 meters
∵ To make the drapes she needs 22 yards
- Use the ratio method
→ Yard : Meter
→ 1 : 0.91
→ 22 : x
- By using cross multiplication
∴ 1(x) = 0.91(22)
∴ x = 20.02 meters
Jasmine needs 20.02 meters to make the drapes
Learn more:
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