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Nezavi [6.7K]
3 years ago
13

X+2=19 write a story

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
6 0
X=17

jack and jill went up the hill

THE END
Alborosie3 years ago
4 0

Answer:

explanation

x+2=19 equation 1

x=19-2

x=17

put value of x in equation 1

17+2=19

19=19

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Is 21:15 equivalent to 7:5
Vera_Pavlovna [14]

Answer:

Yes

Step-by-step explanation:

21/3=7

15/3=5

3 0
3 years ago
Read 2 more answers
What are the solutions of the quadratic equation 0 = 4(x - 3)2 - 16?
erastovalidia [21]

Answer:

 x = 5, x = 1

Step-by-step explanation:

The quadratic equation 0 = 4(x - 3)2 - 16.

Using binomial theorem, (a - b)2 = a2 - 2ab + b2 to expand (x - 3)2.

0 = 4(x2 - 6x + 9 ) - 16.

Using distributive property to multiply 4 by x2 - 6x + 9.

0 = 4x2 - 24x + 36 - 16.

Subtract 16 from 36 to get 20.

0 = 4x2 - 24x + 20.

4x2 - 24x + 20 = 0.

Divide both sides by 4.

x2 - 6x + 5 = 0.

To solve the equation, factor and rewrite as x2 + ax + bx + 5

a + b = -6, ab = 1(5) = 5.

a = -5, b = -1.

Rewriting x2 - 6x + 5 as

(x2 - 5x) + (-x + 5)

Factor x in the first and -1 in the second group.

x(x - 5) - (x - 5)

Factor out common term

(x - 5)(x - 1)

By solving the above, we get

x = 5, x = 1

8 0
2 years ago
What is a cubic polynomial function with zeros 3,3 and -3? show your work.​
Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

Or

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0

So, cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

4 0
3 years ago
AC=CE and D is the midpoint of CE. If CE = 10x+18 DE = 7x-1 and BC = 9x-3 find AB
Mazyrski [523]

We know the CE = 10x + 18 and DE = 7x - 1 and D is the midpoint of CE

⇒ CE = 2 * DE

⇒ 10x + 18 = 2 * (7x - 1)

⇒ 10x + 18 = 14x - 2

⇒ -4x = -20

⇒ x = 5

Now we also know that BC = 9x - 3 and AC = CE = 10x + 18

⇒ AB = AC - BC

⇒ AB = 10x + 18 - (9x - 3)

⇒ AB = x + 21

Substituting the value of x,

⇒ AB = 5 + 21

⇒ AB = 26

Hence, the value of AB is 26 units.


8 0
3 years ago
A runner runs around a circular track. He completes one lap at a time of t = 269 s at a constant speed of v = 4.6 m/s. What is t
AURORKA [14]

Answer:

\boxed{\text{197 m}}

Step-by-step explanation:

The formula relating distance (d), speed (s), and time (t) is

d = st

1. Calculate the distance

d = 269 s × 4.6 m·s⁻¹ = 1240 m

2.Calculate the track radius

The distance travelled is the circumference of a circle

\begin{array}{rcl}C & = & 2 \pi r\\1240 & = & 2 \pi r\\\\r & = & \dfrac{1240}{2 \pi }\\\\& = & 197\\\end{array}\\\text{The radius of the track is }\boxed{\textbf{197 m}}

5 0
4 years ago
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