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2 years ago

Why are these triangles similar?

Mathematics

1 answer:

AveGali [126]2 years ago

4 0

Answer:

I think they are similar by SAS.

Step-by-step explanation:

Both triangles may not be the same size, but they have similar sides and similar angles.

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How do we solve for x

blondinia [14]

X/2 + 5 = -10
x/2 = -10 - 5
x/2 = -15
x = -15(2)
x = -30

3 0

3 years ago

2x+3y + 2z = 0<br>5x – 3y +4=1<br>7x+9y-4z=11

Butoxors [25]

Download photograph !

4 0

3 years ago

Given f(x)=-2x-1, solve for x when f(x)=-7

Svetlanka [38]

Answer:

The answer is -15.

Step-by-step explanation:

1. 2x - 1

2. 2(-7) - 1

3. (-14) - 1

4. -15

By plugging in our x value, we are able to use PEMDAS to multiply 2 and the value of x and then, we subtract 1 from the value we got from step 3 to get -15.

5 0

2 years ago

Help!! Giving brainless need help

charle [14.2K]

Answer:

A. 15

Step-by-step explanation:

V of a right prism which this is. Is LxWxH

So 1.5x 4x2.5=15

4 0

3 years ago

Read 2 more answers

Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m

Molodets [167]

Answer:

$\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1$ .

Step-by-step explanation:

We want to find $\lim_{x \to 2^-} \frac{|x-2|}{x-2}$ .

By definition:

$|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:$

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}$ .

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1)$ .

The limit of a constant is the constant.

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1$ .

8 0

3 years ago