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Iteru [2.4K]
2 years ago
6

Create a system of linear equations that when solved algebraically, prove to have no solution.

Mathematics
1 answer:
ZanzabumX [31]2 years ago
4 0

Answer: y = 3x + 4 and y = 3x + 7

Step-by-step explanation:

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Twice a number is 12 more than five times the number
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N x 2 = 12 + 5n
2n - 5n = 12
-3n = 12
3n = -12
n = -4
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3 years ago
You are taking a quiz that has 9 multiple-choice questions. If each question has 4 possible answers, how many different ways are
11111nata11111 [884]

Answer:

9 questions x 4 answers per question

9x4= 36

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3 years ago
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What is the volume of a box with a height of 3/2 inches, a length of 7/2 inches, and a width of 5/2 inches.
JulsSmile [24]

Answer:

13.125 cubic inches

Step-by-step explanation:

Volume of box is 3/2 X 7/2 X 5/2 = 105/8 = 13 1/8 = 13.125 cubic inches  

4 0
3 years ago
A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.
noname [10]

Answer:

Width = 4ft

Height = 4ft

Length = 8ft

Step-by-step explanation:

Given

Volume = 128ft^3

L = 2W

Base\ Cost = \$9/ft^2

Sides\ Cost = \$6/ft^2

Required

The dimension that minimizes the cost

The volume is:

Volume = LWH

This gives:

128 = LWH

Substitute L = 2W

128 = 2W * WH

128 = 2W^2H

Make H the subject

H = \frac{128}{2W^2}

H = \frac{64}{W^2}

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

A = LW + 2(WH + LH)

The cost is:

Cost = 9 * LW + 6 * 2(WH + LH)

Cost = 9 * LW + 12(WH + LH)

Cost = 9 * LW + 12H(W + L)

Substitute: H = \frac{64}{W^2} and L = 2W

Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)

Cost =18W^2 +  \frac{768}{W^2}*3W

Cost =18W^2 +  \frac{2304}{W}

To minimize the cost, we differentiate

C' =2*18W +  -1 * 2304W^{-2}

Then set to 0

2*18W +  -1 * 2304W^{-2} =0

36W - 2304W^{-2} =0

Rewrite as:

36W = 2304W^{-2}

Divide both sides by W

36 = 2304W^{-3}

Rewrite as:

36 = \frac{2304}{W^3}

Solve for W^3

W^3 = \frac{2304}{36}

W^3 = 64

Take cube roots

W = 4

Recall that:

L = 2W

L = 2 * 4

L = 8

H = \frac{64}{W^2}

H = \frac{64}{4^2}

H = \frac{64}{16}

H = 4

Hence, the dimension that minimizes the cost is:

Width = 4ft

Height = 4ft

Length = 8ft

8 0
2 years ago
Please help asap What is the sum of the following two polynomials?<br> (3x2 – 5x + 3) and (-x2 – 3x)
Anton [14]
(3x^2 - 5x +3) + (-2x -3x)
=3x^2-5x+3 + (6x^2)
=9x^2-5x+3
4 0
2 years ago
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