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Iteru [2.4K]
3 years ago
6

Create a system of linear equations that when solved algebraically, prove to have no solution.

Mathematics
1 answer:
ZanzabumX [31]3 years ago
4 0

Answer: y = 3x + 4 and y = 3x + 7

Step-by-step explanation:

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Select the correct answer from each drop-down menu.
Ahat [919]

Answer:

Cos θ  = -4/5

Tan θ = -3/4

Step-by-step explanation:

The question is as following:

Select the correct answer from each drop-down menu.

Angle θ lies in the second quadrant, and sin θ =3/5.

cos θ = -4/5, -3/5, 3/5, 4/5

tan θ = -4/3, -3/4, 3/4, 4/3

==================================================

Since, the angle lies in second quadrant (negative x axis and positive y axis) we can deduce that cos θ is negative and tan θ is also negative.

If sin θ =3/5

cos \  \theta =\sqrt{1-sin^2 \theta} = \sqrt{1-(\frac{3}{5} )^2} =\sqrt{1-\frac{9}{25} }=\sqrt{\frac{16}{25} } =\frac{4}{5}

∴ Cos θ = -4/5 ⇒ because θ lies in the second quadrant.

And

Tan θ = (sin θ)/(cos θ) = (3/5) / (-4/5) = -3/4.

3 0
3 years ago
The color of any object depends upon which colors are reflected and absorbed. True or False?
SSSSS [86.1K]

Answer:

true

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
PLS HELP 10 points I’m in a test and I killed all my brain cells at 3 am yesterday
sp2606 [1]

Answer:

5/12

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the answer to this eqaution 20 ÷ 15/16
stepladder [879]

Answer:

21 1/3

Step-by-step explanation:

20 ÷ 15/16=

20/1 ÷ 15/16=

20/1*16/15=

4/1*16/3=

64/3=

21 1/3

3 0
3 years ago
the numbers 1,2,3,4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacet. find t
Tresset [83]

Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count Pr(A|B).

Use formula for conditional probability:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.

1. The event A\cap B consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event A\cap B is

Pr(A\cap B)=\dfrac{1}{20}.

2. The event B consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event B is

Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.

3. Then

Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.

Answer: \dfrac{1}{2}.

5 0
3 years ago
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