Create a system of linear equations that when solved algebraically, prove to have no solution.

Write the standard form of the equation of the circle that passes through the point

AnnZ [28]

Answer:

The standard form of the equation of the circle is $x^2+y^2=1$ .

Step-by-step explanation:

A circle is the set of points in a plane that lie a fixed distance, called the radius, from any point, called the center.

The equation of a circle in standard form is

$(x-h)^2+(y-k)^2=r^2$

where r is the radius of the circle, and h, k are the coordinates of its center.

When the center of the circle coincides with the origin $h=k=0$ , so

$(x-0)^2+(y-0)^2=r^2\\x^2+y^2=r^2$

We are also told that the circle contains the point (0, 1), so we will use that information to find the radius r.

$0^2+1^2=r^2\\r^2=0^2+1^2\\r^2=1\\r=\sqrt{1}$

Therefore, the standard form of the equation of the circle is $x^2+y^2=1$ .

5 0

3 years ago

Suppose that there are five young women and six young men on an island. Each woman is willing to marry some of the men on the is

pochemuha

Answer:

Based on the current information, the last man remaining unmarried will be a choice between two

Jason marries Anna

Matt marries Elizabeth

Kevin marries Barbara

Larry marries Diane

Carol can marry either Nick or Oscar

Step-by-step explanation:

The basic method to sort which woman will be marrying which man is simple.

We have to extract the choice by comparing choices of each woman side by side and then selecting the least common one and hence sorting one by one.

First, let's name all the women and men

1. Anna

2. Barbara

3. Carol

4. Diane

5. Elizabeth

We will refer to them with the initial letter of their name . A for Anna, B for Barbara, C for Carol, D for Diane, E for Elizabeth.

The men :

1. Jason

2. Larry

3. Matt

4. Kevin

5. Oscar

6. Nick

And they will be referred as J for Jason, L for Larry, M for Matt, K for Kevin, O for Oscar and N for Nick.

Options for A : J , L ,M

Options for B : K, L

Options for C : J, N , O

Options for D : J, L , N , O

Options for E : J, M

As we can see , no one else wants Kevin other than Barbara so :

Kevin marries Barbara

Moving onwards:

Elizabeth can marry either Jason or Matt,

Meanwhile Anna can marry either Jason , Larry or Matt

Hence,

Matt marries Eilzabeth

as Anna has two more choices still which are Jason and Larry.

Further, seeing the options for Carol and Diane

Carol can marry either Jason, Nick or Oscar while Diane can marry Larry as well as Jason , Nick and Oscar

We can select Jason as the match for Anna as Larry is also a choice for Diane.

Hence, Jason marries Anna

Now we are left with Larry , Nick and Oscar.

Since Carol can only decide from Nick and Oscar but Diane can decide from Larry, Nick and Oscar. Larry is the ideal option for Diane

so, Larry marries Diane

Now in the end, Carol can either choose between Nick or Oscar.

If she chooses Nick to marry, Oscar is left single

If she chooses Oscar to marry, Nick is left single.

7 0

3 years ago

Evaluate: p+2c +3f+6t when p= 15, c=7, f = -3, and t= 1.

frosja888 [35]

This is what I got I tried to underline to show u what I was doing and and how I did it

8 0

3 years ago

Prove sin^2 theta-sin^2 theta is sin tetha sin 3 theta how to prove..pls help!! thanksss

Artemon [7]

Simply you can substitute theta=45 degrees (or any angle,not zero) in left hand side and right hand side.

or

using a^2 - b^2 =(a+b)(a-b)

= sin(2x+x)sin(2x-x)
= sin 3x sin x

3 0

3 years ago

Find the radius of a sphere with a volume of 4.5π cubic centimeters.

Nutka1998 [239]

1.02 is the answer to your question

4 0

3 years ago