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Kipish [7]
3 years ago
7

What is (square root symbol) 12x^2yz^7 in simplest radical form

Mathematics
1 answer:
liraira [26]3 years ago
8 0
That is like ((12)^ 2xyz)^7

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25POINTS!!!
Anastasy [175]

i. Let t be the line tangent at point J. We know that a tangent line at a  point on a circle, is perpendicular to the diameter comprising that certain point.

So t is perpendicular to JL


let l be the tangent line through L. Then l is perpendicular to JL

 

ii. So t and l are 2 different lines, both perpendicular to line JL.


2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.


Remark. Draw a picture to check the steps

4 0
3 years ago
Read 2 more answers
On a loan of $1200 at 15% annual interest, Shirley had to pay $135 interest. For how many months did she have the loan?
natulia [17]

Answer:

<u><em>9 months</em></u>

Step-by-step explanation:

Principal= P= $1200

Rate=R= 15%

Interest= I= $135

Time= T= ?

I=P*R*T/100

135= 1200*15*T/100

135*100=18000*T

13500/18000=T

T= 0.75 years

T= 0.75*12= 9 months

3 0
3 years ago
Read 2 more answers
Chaya’s gross pay is $457.88. The amount of social security deducted is 6.2% or gross pay.
aliya0001 [1]
Just find 6.2% of 457.88
6.2%=6.2/100=0.062

0.062 tiemes 457.88=28.388 rouned 28.39

C
3 0
3 years ago
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Rewrite as a simplified fraction.<br> \large{2.1\overline{6} = ?}2.1 <br> 6<br> =?
slamgirl [31]

Answer:

Note that

0.16666...is equivalent to 1/6

Step-by-step explanation:

We can use the sum of fractions to write out the decimal:

For this particular question, we can see that

0.16666...is the fraction 1/6, therefore

the given decimal

2.16666...=2+1/6=13/6

6 0
3 years ago
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =
geniusboy [140]

The Lagrangian,

L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)

has critical points where its partial derivatives vanish:

L_x=1-\lambda-2\mu x=0

L_y=2+\lambda-2\mu y=0

L_z=9-\lambda=0

L_\lambda=x-y+z-1=0

L_\mu=x^2+y^2-1=0

L_z=0 tells us \lambda=9, so that

L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu

L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}

Then with L_\mu=0, we get

x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2

and L_\lambda=0 tells us

x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}

Then there are two critical points, \left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right). The critical point with the negative x-coordinates gives the maximum value, 9+\sqrt{185}.

8 0
4 years ago
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