<h2><u>Answer</u><u> </u><u>:</u></h2>
![\bigstar\boxed{\large\bf{\leadsto 6\:floors}}](https://tex.z-dn.net/?f=%5Cbigstar%5Cboxed%7B%5Clarge%5Cbf%7B%5Cleadsto%206%5C%3Afloors%7D%7D)
⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀
![\begin{gathered}\rm{ \underline{ \underline{ \red{Given}}}}\begin{cases}\sf{height\:of\:one\:floor\:of\:dollhouse =12.4\:in} & \\ \\\sf{Height\:of\: dollhouse=75\:in}&\end{cases}\\\\\end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%5Crm%7B%20%5Cunderline%7B%20%5Cunderline%7B%20%5Cred%7BGiven%7D%7D%7D%7D%5Cbegin%7Bcases%7D%5Csf%7Bheight%5C%3Aof%5C%3Aone%5C%3Afloor%5C%3Aof%5C%3Adollhouse%20%3D12.4%5C%3Ain%7D%20%26%20%5C%5C%20%5C%5C%5Csf%7BHeight%5C%3Aof%5C%3A%20dollhouse%3D75%5C%3Ain%7D%26%5Cend%7Bcases%7D%5C%5C%5C%5C%5Cend%7Bgathered%7D%20)
<h2><u>To </u><u>find </u><u>:</u></h2>
- Total number of Floors in dool house
<u>➜</u><u> </u><u>Therefore</u><u> </u><u>,</u><u> </u><u>Total</u><u> </u><u>number</u><u> </u><u>of </u><u>floors</u><u> </u><u>can </u><u>be </u><u>find </u><u>out</u><u> </u><u>by </u><u>dividing</u><u> </u><u>the </u><u>total</u><u> </u><u>height</u><u> </u><u>of </u><u>dollhouse</u><u> </u><u>by </u><u>the </u><u>length</u><u> </u><u>of </u><u>one </u><u>floor</u>
![\bf{=\cancel{ \dfrac{75}{12.5}}}](https://tex.z-dn.net/?f=%5Cbf%7B%3D%5Ccancel%7B%20%5Cdfrac%7B75%7D%7B12.5%7D%7D%7D)
![\bf{= 6}](https://tex.z-dn.net/?f=%5Cbf%7B%3D%206%7D)
⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀
What you can do is divided 96 by 8 and it will give you the answer
Very interesting wording but from what I gathered, scaling down by a factor of 1/10 would be 64- 6.4(1/10 of 64) so your final answer would be 57.6
Hope this explanation helps ;)
Answer: 2.01
Step-by-step explanation:
![5\ln x=3.5\\\\x=\frac{3.5}{5}\\\\x=e^{3.5/5}\\\\x \approx 2.01](https://tex.z-dn.net/?f=5%5Cln%20x%3D3.5%5C%5C%5C%5Cx%3D%5Cfrac%7B3.5%7D%7B5%7D%5C%5C%5C%5Cx%3De%5E%7B3.5%2F5%7D%5C%5C%5C%5Cx%20%5Capprox%202.01)