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3 years ago

PLS HELP!!! TYSMMMM

Mathematics

1 answer:

Verdich [7]3 years ago

8 0

Answer:

The ar of plot not fenced = 31.59 x 31 = 979.44 sq mts

Step-by-step explanation:

Let the area of the plot which is fenced be 48x and the area of the plot which is not fenced is 31x.

Hence the total area of the plot will be

48x+31x=79x

Here we also given that , total area of plot is 2496 sq mts.

Hence 79x=2496

Dividing both sides by 79 we get ,

x= 31.59

Hence amount of plot fenced = 31.59 x 48 = 1516.55 sq mts.

The amount of plot not fenced = 31.59 x 31 = 979.44 sq mts

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Alexeev081 [22]

Answer:

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Step-by-step Explanation:

Given:

∆UVW,

m < U = 33°

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Required:

Area of ∆UVW

Solution:

Find side length UV using Law of Sines

$\frac{u}{sin(U)} = \frac{w}{sin(W)}$

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W = 180 - (33+113) = 34°

w = UV = ?

$\frac{29}{sin(33)} = \frac{w}{sin(34)}$

Cross multiply

$29*sin(34) = w*sin(33)$

Divide both sides by sin(33) to make w the subject of formula

$\frac{29*sin(34)}{sin(33)} = \frac{w*sin(33)}{sin(33)}$

$\frac{29*sin(34)}{sin(33)} = w$

$29.77 = w$

$UV = w = 30 m$ (rounded to nearest whole number)

Find the area of ∆UVW using the formula,

$area = \frac{1}{2}*u*w*sin(V)$

$= \frac{1}{2}*29*30*sin(113)$

$= \frac{29*30*sin(113)}{2}$

$Area = 400.4 m^2$ (to nearest tenth).

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Step-by-step explanation:

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Step-by-step explanation: