12.73 GB total when rounded to the nearest 100th.
3.5/27.5=y
y•100= 12.73
Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
She had 18 to start with because when you multiply 4 by 2 it’s 8, so then you add 8 to 10 which is 18.
Answer:
y = 1.5x + 4
Step-by-step explanation:
Slope = (y2-y2)/(x2-x1)
= (1-4)/(-2-0) = -3/-2 = 3/2
y = (3/2)x + c
When x=0, y=4 (y-intercept is 4)
y = (3/2)x + 4
y = 1.5x + 4