The probability of student A is 15/44
Given student A is 70% of time and student B is 60% of time
We need to find the probability of student A
Using formula of conditional probability is P(X/Y) = P(X and Y) / P(Y)
Here X = A and Y = A or B
Therefore,
P(A/A or B) = P(A and (A OR B) / P (A or B)
Now, There is none complement for at least 1
We know that Student A attends 70 % of time
So , his absence is 30% of the time .
Hence the probability of absence is 0.3
Now Considering B in the similar way
We get,
Probability of the absence is 0.4
They are both absent (0.3)(0.4)= 0.12
Here we can say that 12 % of time both are absent
So one or another present on that time is 88%
The probability of present of the time is 0.88
Now calculating the probability,
P(A/A or B) = P(A and (A OR B) / P (A or B)
= 0.3/0.88
= 30/88
= 15/44
Hence the Probability Of A is 15/44
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