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tigry1 [53]
3 years ago
7

A population of 50 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain up to 400 deer.

Absent constraints, the population would grow by 90% per year.
Estimate the population after one year
p1 =___________Estimate the population after two years

p2=_____________
Mathematics
2 answers:
Mars2501 [29]3 years ago
8 0

Answer:

p1= 95, p2 = 180

Step-by-step explanation:

We have population : 50 given that population grows by 90% per year

So, After one year: new population (p1) will be

p1 = 50 + 50*0.9 = 50 + 45 = 95

Now, After two years: new population (p2) will be

p2 = 95 + 95*0.9 = 95 + 85.5 (approximately = 86) = 95 + 86 = 180

Therefore,

p1 = 95, and p2 = 180.

hichkok12 [17]3 years ago
3 0

Answer:

As in the problem states that 90% incremental in population  each year

P1=50+0.9*50

p1=95

P2=95+0.9*95=180

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BaLLatris [955]

Answer:

V=167.5 cubic mm

Step-by-step explanation:

Volume of the Cone is given with the formula

V=\frac{1}{3} \pi r^2h

though we are not specified what is radius and which one is the height , we are assuming that ,

Height = 10 mm

Radius = 4 mm

Substituting these values in the formula we get

V=\frac{1}{3} \pi 4^2 \times 10

V=\frac{1}{3} \pi 160

V=\frac{160 \times 3.14}{3}

V=\frac{160 \times 3.14}{3}

V=\frac{502.40}{3}

V=167.5

3 0
4 years ago
6TH GRADE MATH. PLEASE HELP! 25 POINTS!
Helen [10]

Answer:

Express as exponents) 1) 81 / 2) 4/9 3) -64

Challange: Use parenthesis) 1) 3b 2) 8x^3y^3 3)15x^2y^2

Evaluate) 1) 125 2) 81/256

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Step-by-step explanation:

6 0
3 years ago
Help me please! solve for x.
ohaa [14]

Answer:

x =±sqrt(225) =  ±15

Step-by-step explanation:

x^2 = 225

Take the square root of each side

sqrt(x^2) = ±sqrt(225)

x =±sqrt(225) =  ±15

5 0
4 years ago
Write 2/3 and 3/4 with a common denominator.
maksim [4K]
8/12 and 9/12. hope this helps
5 0
3 years ago
Solve this please!! I'm really stuck
lora16 [44]

Answer:

-74.

Step-by-step explanation:

First, notice that we can divide it into 2 equations (1 on each side of the equal symbol).

<h3>1st step:</h3>

Replace where's x by -2 in the left equation:

x+\:-4+\:-2(3x-5)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:replace\:x\:by\:-2}\\-2+\:-4+\:-2((3\cdot-2)-5)=\square\mathrm{\:\:\:\:solve\:the\:multiplication}\\-2-4-2(-6-5)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:remove\:excess\:symbols}\\-2-4-2(-11)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:solve\:multiplication}\\-2-4+22=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:solve\:subtraction}\\16=\square

<h3>2nd step:</h3>

Now, we will replace the squares with 16 in the second equation. Look:

\square +-4+-2(3\cdot\square\cdot-5)=\triangle\\16 +-4+-2(3\cdot16-5)\\16-4-2(48-5)\\16-4-2(43)\\16-4-86\\=-74

So, the answer is -74.

<h2>We also can solve it in another way:</h2>

x-4-2(3x-5)=\\x-4-6x+10\\-5x+6\\\\\mathrm{let's\:replace\:x\:by\:-2:}\\-5\cdot(-2)+6\\10+6\\=16

Now let's call the gray square as y in the second equation:

y-4-2(3y-5)\\y-4-6y+10\\-5y+6\\\\\mathrm{let's\:replace\:y\:by\:16:}\\-5\cdot(16)+6\\-80+6\\=-74

So, your final answer is -74.

Hope it helps! :D

7 0
2 years ago
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