The original surface area is:
A = 2 * pi * r ^ 2 + 2 * pi * r * h
Where,
r: radio
h: height
The area when the dimensions are modified is:
A '= 2 * pi * (4r) ^ 2 + 2 * pi * (4r) * (4h)
Rewriting we have:
A '= 16 * 2 * pi * r ^ 2 + 16 * 2 * pi * r * h
A '= 16 (2 * pi * r ^ 2 + 2 * pi * r * h)
A '= 16A
Answer:
the new surface area would be 16 times bigger than the original surface area
Answer:
1,2, 1,203, 12,03, 12,3, 12,301
Step-by-step explanation:
1,2 → 1,200
1,203
12,3 → 12,300
12,301
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Answer:
M = Log (10S/S)
Step-by-step explanation:
We are told that the magnitude, M, of an earthquake is defined to be;
M = Log l/S
Where I is intensity and S is standard earthquake.
Now, we want to find the magnitude of an earthquake that is 10 times more intense than a standard earthquake
Since 10 times more intense than standard earthquake, it means that;
I = 10S
So plugging in 10S for I in the original equation for magnitude gives;
M = Log (10S/S)
Answer:
see explanation
Step-by-step explanation:
To find the second and fifth terms substitute n = 2 and n = 5 into the rule, that is
(a)
= 3(2)² - 1 = (3 × 4) - 1 = 12 - 1 = 11
(b)
= 3(5)² - 1 = (3 × 25) - 1 = 75 - 1 = 74
Thus the second term is 11 and the fifth term is 74
2 divided by 5 = 0.4
2/5 = 0.4
2/5 is equal to 0.4