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Vikentia [17]
4 years ago
12

Which of the following is a rational number

Mathematics
1 answer:
Feliz [49]4 years ago
5 0
The answer is the square root of 16
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What is 4 divided by 2.42?
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For each number, name its opposite.
sweet [91]

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a. 5

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4 0
2 years ago
If 1/5 of those in a high school are freshmen, and 40% of the freshmen are women, and 3/5 of those in the other grades are women
murzikaleks [220]

There are 264 male students in the high school containing 600 students.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

There are 600 students altogether, hence:

Number of freshmen = (1/5) * 600 = 120

Number of other graders = 600 - 120 = 480

Number of male freshmen = 120 - (0.4 * 120) = 72

Number of male other graders = (1 - 3/5) * 480 = 192

Total number of male = 72 + 192 = 264

There are 264 male students in the high school containing 600 students.

Find out more on equation at: brainly.com/question/1214333

4 0
2 years ago
NO LINKS! Please help me with this problem
Dafna11 [192]

Answer:

\frac{x^2}{9}+\frac{y^2}{4}=1

Step-by-step explanation:

So an ellipse can be expressed in two different but very similar forms:

<u><em>Horizontal Major Axis:</em></u>

   \frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1

<u><em>Vertical Major Axis</em></u>:
   \frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1

In both equations the length of the major axis is "2a" and the length of the minor axis is "2b"

In the equation you provided, the major axis is horizontal, and the minor axis is vertical.

So looking at the horizontal length, you can see that it's 6, and since this ellipse has a horizontal major axis, that means 2a=6, which means a=3

Looking at the vertical length, you can see that it's 4, and since the ellipse has a vertical minor axis, that means 2b=4, which means b=2

The last thing to note is that the center of an ellipse is (h, k) in the equation, and since here the center is (0, 0) it's (x-0)^2 and (y-0)^2 in the denominator which is just x^2 and y^2

So let's plug in the values into the equation:

\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1

(h, k) = (0, 0)

a = 3

b = 2

\frac{x^2}{3^2}+\frac{y^2}{2^2}=1\\\\\frac{x^2}{9}+\frac{y^2}{4}=1

7 0
2 years ago
Read 2 more answers
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