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My name is Ann [436]
3 years ago
9

If i = −1 and a and b are non-zero real numbers, what is 1a+bi ?

Mathematics
1 answer:
MariettaO [177]3 years ago
6 0
The i you normally think of (the one = to sqrt(-1) is not the same i they are using here. They are using this i the same way you would use x = - 1 in any normal equation or relation.

1a + b(-1)
a - b is your answer <<<< answer
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Two sides of a triangle measure 10 inches and 10.9 inches. The included angle between these sides is 65°. What is the approximat
fenix001 [56]

Answer:

9.9inches

Step-by-step explanation:

From the attachment, the opposite side is debited as "x" while the Hypotenuse is 10.9inches, we can find the third side by using trigonometry

From trigonometry, Sin(x)= opposite/Hypotenuse

Sin(65)=X/10.9

X= Sin(65) ×10.9

X=0.9063×10.9

=9.8688

Hence the third side of the triangle is approximately 9.9inches

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6 0
3 years ago
Find the factors of f(x), given that x = −2 is a zero. HELP PLEASE!!
seropon [69]

Answer:

First Option is correct.

(x+2)(x+3)(x-4)

Step-by-step explanation:

Given:

The given factor is.

f(x)=x^{3}+x^{2}-14x-24

We need to find the factors of given factor.

Solution:

f(x)=x^{3}+x^{2}-14x-24

Substitute (-4x-10x) in the place of -14x

f(x)=x^{3}+x^{2}-4x-10x-24

Rearrange the equation:

f(x)=(x^{3}-4x)+(x^{2}-10x-24)

Now we factorised the above equation.

The factors of x^{2} -10x-24=(x+2)(x-12)

Now we substitute (x+2)(x-12) in the place of x^{2} -10x-24

And in the place of x^{3}-4x=x(x^{2}-4)

f(x)=x(x^{2}-4)+(x+2)(x-12)

Simplify x^{2} -4=x^{2} -(2)^{2} = (x+2)(x-2)

f(x)=x[(x+2)(x-2)]+(x+2)(x-12)

Common factor for above function (x+2)

f(x)=(x+2)[x(x-2)+(x-12)]

Simplify.

f(x)=(x+2)[x^{2}-2x+x-12]

f(x)=(x+2)(x^{2}-x-12)

The factor of x^{2}-x-12=x^{2}-4x+3x-12=x(x-4)+3(x-4)=(x-4)(x+3)

So the factors of the function.

f(x)=(x+2)(x-4)(x+3)

Therefore, the factors of the given function are (x+2)(x-4)(x+3)

4 0
3 years ago
Find the inverse of the function f(x)=x^2+9
Vikki [24]
-9+x ?
I don’t know if this is the right answer
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