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valentina_108 [34]
3 years ago
9

Write a polynomial equation of degree 3 such that two of its roots are 2 and an imaginary number.

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
5 0
X^3 - i(x)^2 - 4x + 4i ....
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Find the value of X.
pychu [463]

Answer:

<h2><em>x</em><em>=</em><em>3</em></h2>

<em>Sol</em><em>ution</em><em>,</em>

<em>Theorem</em><em>:</em>

<em>The</em><em> </em><em>angle</em><em> </em><em>bisector</em><em> </em><em>theorem</em><em> </em><em>states </em><em>that</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>ray </em><em>bisects</em><em> </em><em>an</em><em> </em><em>angle</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>triangle,</em><em>then</em><em> </em><em>it</em><em> </em><em>divides</em><em> </em><em>the</em><em> </em><em>oppos</em><em>ite</em><em> </em><em>side</em><em> </em><em>into</em><em> </em><em>two </em><em>segments</em><em> </em><em>that</em><em> </em><em>are</em><em> </em><em>proportional</em><em> </em><em>to</em><em> </em><em>other</em><em> </em><em>two</em><em> </em><em>sides</em><em>.</em>

<em>By</em><em> </em><em>the</em><em> </em><em>theorem</em><em>,</em>

<em>\frac{24}{9x - 9}  =  \frac{32}{6x + 6}  \\ or \: 24(6x + 6) = 32(9x - 9) \\ or \: 144x + 144 = 288x - 288 \\ or \: 144x - 288x =  - 288 - 144 \\ or \:  - 144x =  - 432 \\ or \: x =  \frac{ - 432}{ - 144}  \\ x = 3</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>

3 0
3 years ago
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Mariulka [41]

Answer:

14824

Step-by-step explanation:

the product is 14824

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