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hjlf
3 years ago
13

The slope-intercept form of the equation of a line that passes through point (–2, –13) is y = 5x – 3. What is the point-slope fo

rm of the equation for this line?
y – 13 = 5(x – 2)
y + 13 = 5(x + 2)
y – 2 = 5(x – 13)
y + 2 = 5(x + 13)
Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0
Point slope form: y-y₁=5(x-x₁)

y+13=5(x+2)
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5x+2y=22. -2x+6y=3 What is the X coordinate of the solution. Round to the nearest tenth
just olya [345]
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Find the product of the greatest common divisor and the least common multiple of 18 and 42.
Evgesh-ka [11]

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ABC has coordinates of A(-8,-8) B(4,-2) C(2,2). Find the coordinates of its image after the dilation centered at the origin with
garri49 [273]

Answer:

A' ( -12 , -12 )

B' ( 6 , -3 )

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Step-by-step explanation:

To find the coordinates of a point after a dilation simply multiply the x and y values of the points by the scale factor

Points: A(-8,-8) B(4,-2) C(2,2)

Scale factor: 1.5

Coordinates after the dilation

A' = (-8,-8) --------> (-8 * 1.5 , -8 * 1.5 ) ------------> (-12 , -12)

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C' = (2 , 2) ----------> (2 * 1.5 , 2 * 1.5) -----------> (3, 3)

So inclusion the coordinates of ABC after a dilation centered at the origin with a scale factor of 1.5 are A' ( -12 , -12 ) B' ( 6 , -3 ) C' ( 3 , 3 )

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