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viktelen [127]
3 years ago
9

HELP I NEED HELP ASAP

Mathematics
1 answer:
Natalija [7]3 years ago
3 0

Answer:

Step-by-step explanation:

A is correct,  if it's any help... now?

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Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
2 years ago
(Graphing inequality) where do I go! Left or right!!
Aleksandr-060686 [28]

Answer:

It depends what the problem requests

7 0
3 years ago
Read 2 more answers
4.) Katrina is reading a book that has 384 pages. If she reads 12 pages a day, how many days will it
JulsSmile [24]

384 / 12 = 32.

Long division.

4 0
3 years ago
14. The cost of 10 dozen of caps is Rs.800. How many caps can bebought for Rs.200.​
kvasek [131]

Answer:

123 456lcm divison method

6 0
2 years ago
X^2 -9 divided by x+3
WINSTONCH [101]

Step-by-step explanation:

Hey, there!!

Given that,

\frac{ {x}^{2} - 9 }{x + 3}

{ we can write (a^2-4) as (a^2 - 2^2) also as (x^2- 9) can be written as (x^2 - 3^2)}.

\frac{ {x}^{2} -  {3}^{2}  }{x + 3}

We have a^2-b^2= (a+b) (a-b), so keep same formula on it.

\frac{(x + 3)(x - 3)}{(x + 3)}

(x+3) in numerator and denominator gets cancelled,

(x - 3)

Therefore, (x-3) is the final value.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
3 years ago
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