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Arte-miy333 [17]
3 years ago
10

Mai bought a television for $330. The tax rate is 8%. What is the total amount she paid for the television?

Mathematics
2 answers:
Wewaii [24]3 years ago
6 0

The answer is actually 356.40. I just took the test

EastWind [94]3 years ago
3 0
The total amount Mai paid for the television is $356.40
Explanation: 330*1.08=356.4
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The ratio of a cost of a tennis racket to tennis balls is 18:1 if a can of balls cost $5.35 what is the cost of the racket
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Molodets [167]

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3 0
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Read 2 more answers
Prove that: (Sec A- cosec A)(1+ tan A+cot A) = tan A× sec A - cot A × cosec A
mash [69]

Answer:

Step-by-step explanation:

(sec A-cosecA)(1+tanA+cotA)=tanAsecA-cotAcosecA

we take the LHS so here goes,

(sec A-cosecA)(1+tanA+cotA)=tanAsecA-cotAcosecA\\(\frac{1}{cosA} -\frac{1}{sinA})(1+\frac{sinA}{cosA}+\frac{cosA}{sinA})\\\\(\frac{sinA-cosA}{sinAcosA})(\frac{sinAcosA+sin^2A+cos^2A}{sinAcosA})\\

since , sin^2A+cos^2A=1

the identity becomes,

(\frac{sinA-cosA}{sinAcosA})(\frac{1+sinAcosA}{sinAcosA})\\\\(\frac{sinA+sin^2AcosA-cosA-cos^2AsinA}{sin^2Acos^2A})\\\\

now, we know,

sin^2A=1-cos^2A and cos^2A=1-sin^2A

the identity becomes,

(\frac{sinA+(1-cos^2A)cosA-cosA-(1-sin^2A)sinA}{sin^2Acos^2A} )\\\\

(\frac{sinA+cosA-cos^3A-cosA-sinA+sin^3A}{sin^2Acos^2A})

sin A and cos A cancel out it becomes zero

\frac{sin^3A-cos^3A}{sin^2Acos^2A} \\\\

Splitting the denominator the identity becomes

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Hence,

tanAsecA-cotAcosecA

3 0
3 years ago
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