Divide 3 1/2 by 2/3. 3 1/2 = 7/2 as an improper fraction, so we have 7/2 ÷ 2/3 = 7/2 * 3/2 = 21/4 = 5 1/4 L
Answer:
x = 3 + √6 ; x = 3 - √6 ;
; 
Step-by-step explanation:
Relation given in the question:
(x² − 6x +3)(2x² − 4x − 7) = 0
Now,
for the above relation to be true the following condition must be followed:
Either (x² − 6x +3) = 0 ............(1)
or
(2x² − 4x − 7) = 0 ..........(2)
now considering the equation (1)
(x² − 6x +3) = 0
the roots can be found out as:

for the equation ax² + bx + c = 0
thus,
the roots are

or

or
and, x = 
or
and, x = 
or
x = 3 + √6 and x = 3 - √6
similarly for (2x² − 4x − 7) = 0.
we have
the roots are

or

or
and, x = 
or
and, x = 
or
and, x = 
or
and, 
Hence, the possible roots are
x = 3 + √6 ; x = 3 - √6 ;
; 
(x+3)(x^2-3x+9)
this gets the x^3 while the 3x cancels out and 3*9=27
hope this helps although i didn't explain very well :)
The three consecutive integers are 127, 128, 129
First of all you have to convert kg to grams
so there is 1 kg in 1000g
.4 kg is 400g
1000+400= 1400g
1400-650 = 750 kg
that's your final answer