So before we can decide which graph it is, we have to find the zeros (x-intercepts) of this graph. We can do this by setting y to 0.
Firstly, factor out 3x on the right side of the equation:
Next, use the zero product property to solve y = 0:
So we know that the zeros of this equation are (4,0) and (0,0). Looking at the four graphs, the only graph that has a line crossing those 2 points is the first graph. Therefore, the graph of this equation is the first graph.
Answer:
The lower bound is, and the upper bound is
.
Step-by-step explanation:
Let the random variable <em>X</em> follows a normal distribution with mean <em>μ </em>and standard deviation <em>σ</em>.
The the random variable <em>Z, </em>defined as is standardized random variable also known as a standard normal random variable. The random variable
.
The standard normal random variable has a symmetric distribution.
It is provided that .
Determine the upper and lower bound as follows:
Use a standard normal table to determine the value of <em>z.</em>
The value of <em>z</em> such that P (Z ≤ z) = 0.755 is 0.69.
The lower bound is, and the upper bound is
.