3 years ago

Write an equation of the line with the given slope and y-intercept. slope:1/9, y-intercept: 3

Mathematics

1 answer:

Setler79 [48]3 years ago

8 0

y = 1/9x + 3

The formula of the equation is y = mx + b

M is the slope and b is the y-intercept.

Hope this helps, and have a good day! :]

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Write, in slope intercept form, the equation of the line that passes through (8, -9) and has a slope of -5/4.

dezoksy [38]

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The equation in the slope-intercept form will be:

$y=-\frac{5}{4}x+1$

Step-by-step explanation:

Given

slope = m = -5/4

point = (8, -9)

As we know that the equation of a line in point-slope form is

$y-y_1=m\left(x-x_1\right)$

substituting the values m = -5/4 and point = (8, -9)

$y-\left(-9\right)=\frac{-5}{4}\left(x-8\right)$

$y+9=\frac{-5}{4}\left(x-8\right)$

Writing the equation in slope-intercept form

$y=mx+b$

where m is the slope, and b is the y-intercept

so the equation of the line in slope-intercept form becomes

$y+9=\frac{-5}{4}\left(x-8\right)$

subtract 9 from both sides

$y+9-9=\frac{-5}{4}\left(x-8\right)-9$

$y=-\frac{5}{4}x+1$

Therefore, the equation in the slope-intercept form will be:

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