Y + 8 = 2 i need help!!!!!

Mathematics

2 answers:

skad [1K]3 years ago

8 0

47?g SF jdd Feds dg gc XX

sergey [27]3 years ago

3 0

Answer:

y = -6

Step-by-step explanation:

-6 + 8 = 2

You might be interested in

You have $44000 in a savings account that pays 2% annual interestand the inflatation rate is 3.24%. How much buying power in dol

puteri [66]

At the end of the year ...
the price will be 44,000*1.0324 = 45,425.60
the bank balance will be 44,000*1.02 = 44,880.00

This is 545.60 fewer dollars than required to pay the price.

You lose $545.60 in current-year buying power.

4 0

3 years ago

How does the speed change on the Graph? And what does a steeper line mean?

Mandarinka [93]

The steeper the line is (the larger the slope), the faster the speed is. This is due to the fact that speed=distance/time and the slope=y/x which is distance over time on a distance v time graph.
let me know if you need further explanation by leaving a comment and I hope this helps.

8 0

3 years ago

How much more will $22,000 earn in interest than $14,000 if both are invested in savings accounts with APYS of 5.4% for a year?

xxMikexx [17]

Total = Principal * (1 + rate) ^ year
Total = 22,000 * (1.054)^1 = 23,188.00

Total = 14,000 * (1.054)^1 = 14,756.00

23,188.00 - 22,000 = 1,188.00 interest
14,756.00 - 14,000 = 756.00 interest

So the 22,000 earns (1,188.00 -756.00) = 432.00 more dollars in interest than the 14,000 dollars earns in interest.

6 0

3 years ago

A random sample of 625 10-ounce cans of fruit nectar is drawn from among all cans produced in a run. Prior experience has shown

diamong [38]

Answer:

10.57% probability that the mean contents of the 625 sample cans is less than 9.995 ounces.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 10, \sigma = 0.1, n = 625, s = \frac{0.1}{\sqrt{625}} = 0.004$