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Elden [556K]
1 year ago
5

500 portions of strawberries have been ordered for the tournament, but because of bad weather only

Mathematics
1 answer:
Citrus2011 [14]1 year ago
8 0

We conclude that 375 portions can be sold.

<h3>How many portions can be sold?</h3>

We know that 500 portions have been ordered, but only 5/6 of that was delivered, so the number of delivered portions is:

p = (5/6)*500 = 416.6

Which we can round to the next whole number, 417.

Now we know that 10% of these are given to the players and staff, then the number of portions that can be sold is the 90% of 417, which is:

N = 417*(90%/100%) = 417*0.9 = 375

We conclude that 375 portions can be sold.

If you want to learn more about percentages:

brainly.com/question/843074

#SPJ1

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Write an equation describing the relationship of the given variables. y varies inversely as the cube root of x and when x=125, y
notka56 [123]

Answer:

y = 40 / x^1/3

Step-by-step explanation:

Given that :

y α x^1/3

y = k * 1 / x^1/3

y = k / x^1/3

When x = 125 ; y = 8

8 = k / 125^1/3

Cube root of 125 = 5

8 = k / 5

8 * 5 = k ; k = 40

Hence, expression becomes :

y = 40 / x^1/3

4 0
3 years ago
Billy is a professional baseball player. He had 99 singles, 47 doubles, 4 triples, and 15 home runs in his first year playing. I
Maurinko [17]

Answer: 792

Step-by-step explanation:

From what I got it should be 792 because it is asking for doubles, triples, and home runs all together at the same amount that he got on his first year.

It says after 12 years

Doubles 47 times 12 years = 564

Triples 4 times 12 years = 48

and

Home runs 15 times 12 years = 180

564 + 48 = 612

612 + 180 = 792

8 0
3 years ago
Read 2 more answers
How many photons with 10 ev are required to produce 20 joules of energy?
alexira [117]
1 joule = 6,242e+18ev

20 joule = 20 joule *6,242e+18 ev/joule =1,248e+20 ev

1,248e+20 ev / (10 ev / photon) =1,248e+19 photons.



7 0
3 years ago
13. In A ABC, if m BF is an angle bisector, find<br> m
Tresset [83]

If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.

Given that m∠ABF=41° and BF is an angle bisector.

We are required to find the angle m∠BCE if BF is an angle bisector.

Angle bisector basically divides an angle into two parts.

If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.

In this way ∠ABC=2*∠ABF

∠ABC=2*41

=82°

In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.

∠BCE+∠CEB+EBC=180  (Sum of all the angles in a triangle is 180°)

∠BCE+90+82=180

∠BCE=180-172

∠BCE=8°

Hence if BF is an angle bisector then angle m∠BCE=8°.

Learn more about angles at brainly.com/question/25716982

#SPJ1

4 0
1 year ago
Please help really need to pass
VashaNatasha [74]
First add 5 to right side
\frac{x}{7} = -4+5 = 1
Next , to cancel the 7, you need to multiply by 7 on both sides
x = 1*7 = 7
8 0
3 years ago
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