Solve for y. 2/3+y−1/9=7/9
2 answers:
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we know that
One tens is equal to the number----------->
so
tens is equal to
therefore
<u>the answer is</u>
Given:
The vertices of a parallelogram are P(1,2,1), Q(1,0,-1), R(2,2,0).
PQ and PR are the adjacent sides of the parallelogram.
To find:
The coordinates of vertex S.
Solution:
We know that, the diagonals of a parallelogram bisect each other.
Let the coordinates of the vertex S are (a,b,c).
In the given parallelogram PS and QR are the diagonals. It means their midpoints are same.
On comparing both sides, we get
Similarly,
And,
Hence, the coordinates of vertex S are (2,0,-2).