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Dmitrij [34]
4 years ago
13

(5. 5,000 lb = T I need help now ASAP

Mathematics
1 answer:
pochemuha4 years ago
8 0
2.5 in USA ton, metric ton is 2.267962
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74% of freshmen entering public high schools in 2006 graduated with their class in 2010. A random sample of 81 freshmen is selec
Assoli18 [71]

Answer: Probability that the proportion of students who graduated is greater than 0.743 is P = 0.4755

Step-by-step explanation:

Given that,

Probability of freshmen entering public high schools in 2006 graduated with their class in 2010, p = 0.74

Random sample of freshman, n = 81

Utilizing central limit theorem,

P(\hat{p}

So,

(P(\hat{p}>0.743) = P(Z>0.743 - \frac{0.74}{\sqrt{\frac{0.74(1-0.74)}{81} }  } )

= P( Z > 0.0616)

= 0.4755 ⇒ probability that the proportion of students who graduated is greater than 0.743.

7 0
3 years ago
What are the x-and y-intercepts of the linear function 10x - 20y = 60 ?
dolphi86 [110]

Answer:

Y intercept= - 3

X intercept= 6

Step-by-step explanation:

You can find the y and x intercepts by simply plugging in 0 for x and y and solving the equation from there.

8 0
3 years ago
Solve the following quadratic equation by factorisation method 3 x square - 2 root 6 × + 2 =0​
frozen [14]
3x^2 -2root(6)x + 2 = 0

(root(3)x)^2 -2[root(3)x]root(2)+ (root(2))^2 = 0

let a = root(3)x and b = root(2)

a^2 -2ab + b^2 = 0

(a - b)^2 = 0

by the null factor rule,

a - b = 0

sub back in a and b

root(3)x = root(2)

x = root(3)/root(3)
6 0
3 years ago
following frequency distribution shows the daily expenditure on milk of 30 households in a locality:Daily expenditure on milk(in
valina [46]

<em>Note:</em> <em>As you missed to identify what we have to find in this question. But, after a little research, I am able to find that we had to find the Mode for the data given in your question. So, I am assuming we have to calculate the the Mode. Hopefully, it would clear your concept regarding this topic.</em>

Answer:

The mode of the data = 75

Step-by-step explanation:

Lets visualize the given data in a table to show the frequency distribution:

<em>Daily expenditure on milk (in Rs)           Number of households</em>

<em>                  0-30                                                           5</em>

<em>                 30-60                                                          6        </em>

<em>                 60-90                                                          9</em>

<em>                 90-120                                                         6</em>

<em>                 120-150                                                        4</em>

Here the maximum frequency is 9.

So, modal class is <em>60-90.</em>

<em />

As the formula to calculate the mode:

Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )

Here, the maximum

l_{1} =60, f_{1} =9, f_{0}=6, f_{0}=6, h=30

l= is the lower limit of the class

f_{1} = is the frequency of the modal class

f_{0} = is the frequency of the previous modal class

f_{2} = is the frequency of the next previous modal class

l= is the class size

So,

Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )

Mode = 60 + 30 (\frac{9-6}{2(9)-6-6} )

Mode = 60 + \frac{(30)(3)}{6}

Mode = 60 + 15=75

∴ The mode of the data = 75

<em>Keywords: mode, frequency distribution</em>

<em> Learn more about mode and frequency distribution from brainly.com/question/14354368</em>

<em> #learnwithBrainly </em>

5 0
3 years ago
4×<img src="https://tex.z-dn.net/?f=10%5E%7B3%7D" id="TexFormula1" title="10^{3}" alt="10^{3}" align="absmiddle" class="latex-fo
Anettt [7]
4000 (4x10^3) times 400 (4x10^2) is equal to 16x10^5 ( 1,600,000)
5 0
3 years ago
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