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3 years ago

In emails to monthly readers of a newsletter 3% of the emails come back undelivered

Mathematics

1 answer:

MAXImum [283]3 years ago

4 0

The prediction of the editor is not correct

Step-by-step explanation:

Step 1 :

Given,

Percentage of email that comes back undelivered = 3%

Number of email the editor sends out = 12181

Number of email predicted by the editor which is undelivered = 433

Step 2 :

To compute the actual number of emails undelivered we need to compute 3% of the emails that is actually sent.

= 3% of 12181 = 0.03 * 12181 = 365.43 which is 366 rounded to the closest integer.

Step 3:

Hence we can conclude that the prediction of the editor is not correct as only 366 undelivered notices are received back as against his prediction of 433 notices.

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While waiting for a video game to download, you notice that 30% of 32,000 kilobytes have been downloaded so far.

kirill [66]

9600 kilobytes...
30 x 32000 divided by 100 = 9600
hope this helps!

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3 years ago

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Consider the following sets: R = {x | x is the set of rectangles} P = {x | x is the set of parallelograms} T = {x | x is the set

Liula [17]

"T is a subset of P"

Not true since triangle has three sides but parallelogram has four sides.

"E is a subset of I"

True since equilateral triangles are isosceles triangles with all angles equal.

"S is a subset of T"

True since scalene triangles are still triangle.

"I ⊂ E"

False since there are isosceles triangles those are not equilateral triangles. Namely triangle with angles 20°, 20°, 140°

"T ⊂ E"

False since not all triangles are equilateral. Scalene triangle is one of counterexamples.

"R ⊂ P"

True since rectangles are parallelograms with right angles.

Final answer: <span>E is a subset of I, </span>S is a subset of T, and R ⊂ P.

Hope this helps.

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3 years ago

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Which situations involve descriptive statistics ? Select each correct answer A) a bowler's scorecard shows he threw a strike on

mart [117]

C is the correct answer to your question

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3 years ago

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Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).

Reil [10]

Answer:

Part A) $sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}$

Part B) $tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) $sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}$

Step-by-step explanation:

Part A) Find $sin(\alpha)\ and\ cos(\beta)$

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sin(\alpha)=cos(\beta)$

Find the value of $sin(\alpha)$ in the right triangle of the figure

$sin(\alpha)=\frac{8}{14}$ ---> opposite side divided by the hypotenuse

simplify

$sin(\alpha)=\frac{4}{7}$

therefore

$sin(\alpha)=\frac{4}{7}$

$cos(\beta)=\frac{4}{7}$

Part B) Find $tan(\alpha)\ and\ cot(\beta)$

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$tan(\alpha)=cot(\beta)$

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

$14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132$

$x=\sqrt{132}\ units$

simplify

$x=2\sqrt{33}\ units$

Find the value of $tan(\alpha)$ in the right triangle of the figure

$tan(\alpha)=\frac{8}{2\sqrt{33}}$ ---> opposite side divided by the adjacent side angle alpha

simplify

$tan(\alpha)=\frac{4}{\sqrt{33}}$

therefore

$tan(\alpha)=\frac{4}{\sqrt{33}}$

$tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) Find $sec(\alpha)\ and\ csc(\beta)$

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sec(\alpha)=csc(\beta)$

Find the value of $sec(\alpha)$ in the right triangle of the figure

$sec(\alpha)=\frac{1}{cos(\alpha)}$

Find the value of $cos(\alpha)$

$cos(\alpha)=\frac{2\sqrt{33}}{14}$ ---> adjacent side divided by the hypotenuse

simplify

$cos(\alpha)=\frac{\sqrt{33}}{7}$

therefore

$sec(\alpha)=\frac{7}{\sqrt{33}}$

$csc(\beta)=\frac{7}{\sqrt{33}}$

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3 years ago

A candy manufacturer is interested in the distribution of colors in each of its packages of candy sold. The manufacturer randoml

Otrada [13]

Answer:

Option B

Step-by-step explanation:

Given that a candy manufacturer is interested in the distribution of colors in each of its packages of candy sold. The manufacturer randomly sample packages from multiple batches at one factory.

Because he resorts to only one factory, there may be bias in the sample. Other factories may have different processes of the settings and also if a diversified sample is taken then it is likely to represent the whole population, and hence results would be more accurate

Option A is incorrect since only one factory was done

C and D are not selected because one factory result cannot be generalised to all other factors in the same country or outside.

So answer would be

B) No, because the other factories may have different processes or the settings

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3 years ago