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2 years ago

Angles P and Q are supplementary. If mZP is 32°, what is the mZQ?

Mathematics

1 answer:

Ratling [72]2 years ago

6 0

Step-by-step explanation:

Supplementary angles add up to 180°

$\therefore m\angle P + m\angle Q = 180° \\ \therefore 32 \degree+ m\angle Q = 180° \\ \therefore m\angle Q = 180° - 32° \\ \huge \purple{ \boxed{\therefore m\angle Q = 148°}}$

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Why equals 3/4 X -12 and why equals negative 4X - 31

Helga [31]

Answer:

(x, y) = (-4, -15)

Step-by-step explanation:

Perhaps you want the solution to ...

y = 3/4x -12

y = -4x -31

Equating the two expressions for y gives ...

3/4x -12 = -4x -31

3/4x = -4x -19 . . . . . add 12

3x = -16x -76 . . . . . multiply by 4

19x = -76 . . . . . . . . . add 16x

x = -76/19 = -4 . . . . divide by 19

y = (3/4)(-4) -12 = -15 . . . . use the first equation to find y

The solution to this system of equations is ...

(x, y) = (-4, -15)

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3 years ago

Find the x and y intercepts of the line. 4x-2y=16 need in 5-to minutes PLEASE

crimeas [40]

Y=2x-8 is the answer

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2 years ago

The are of a shaded region is 118 ft squared. Which equation can be- used to find the value of X, in feet?

Triss [41]

Answer:

$x^2+ 18x -130=0$

Step-by-step explanation:

Given

See attachment for diagram

Required

The equation to find x

First, calculate the area of the big rectangle using:

$Area = Length * Width$

So:

$A_1 = (x + 6) * (3x - 2)$

The smaller rectangle

$A_2 = (x - 1) * (2x)$

The difference between this areas give the area of the shaded region.

So:

$A_1 - A_1 = 118$

$(x+6)*(3x-2) - (x-1)*2x = 118$

Open brackets

$3x^2 - 2x + 18x -12 -2x^2 +2x = 118$

Collect like terms

$3x^2 -2x^2- 2x +2x+ 18x -12 - 118=0$

$x^2+ 18x -130=0$

<em>The above equation can be used to solve for x</em>

4 0

2 years ago

Question 1 of 3 NE A scale drawing of a fishing boat has a scale of 1 cmn to 2 meters. If the length of the fishing boat is 6 cm

bagirrra123 [75]

Answer:

12 meters

Step-by-step explanation:

Given

$Scale= 1cm:2m$

Required

Determine the measurement when the scale reads 6cm

Represent this scale with x;

Such that:

$Scale = 6cm:x$

Equate

$Scale= 1cm:2m$ and $Scale = 6cm:x$

$1cm:2m = 6cm:x$

Express as fraction

$\frac{1cm}{2m} = \frac{6cm}{x}$

Cross Multiply

$x * 1cm = 6cm * 2m$

$x * 1 = 6 * 2m$

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3 0

2 years ago

The inverse for f(x)=-.75x

irina [24]

It would be $-\frac{4x}{3}$ .

8 0

3 years ago