Answer:
0.75
Step-by-step explanation:
Given,
P(A) = 0.6, P(B) = 0.4, P(C) = 0.2,
P(A ∩ B) = 0.3, P(A ∩ C) = 0.12, P(B ∩ C) = 0.1 and P(A ∩ B ∩ C) = 0.07,
Where,
A = event that the selected student has a Visa card,
B = event that the selected student has a MasterCard,
C = event that the selected student has an American Express card,
We know that,
P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)
= 0.6 + 0.4 + 0.2 - 0.3 - 0.12 - 0.1 + 0.07
= 0.75
Hence, the probability that the selected student has at least one of the three types of cards is 0.75.
