The like terms are 16x and 2x
Answer:
Step-by-step explanation:
Correct option is
D
[1,(1+π)
2
]
f(x)=(1+sec
−1
(x))(1+cos
−1
(x))
Here the limiting component is cos
−1
(x), since the domain of cos
−1
(x) is [−1,1].
Therefore,
f(1)=(1+0)(1+0)
=1
f(−1)=(1+π)(1+π)
=(1+π)
2
Hence range of f(x)=[1,(1+π)
2
]
<em>I'm sorry and I feel that your probably going to get mad, but we can't answer this question without knowing what those drag-and-drop options are! I hope that you can quickly re-post this, and then I will be able to help you! Sorry!</em>
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<em>Miri</em>
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