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3 years ago

Estimate 68×23 please

Mathematics

1 answer:

bonufazy [111]3 years ago

6 0

I would round 68 to 70 and 23 to 20. Then I would multiply ; 70*20=1400

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Write the equation, in slope-intercept form, of the line that has a slope of 2 and passes through the point (3, 1).

puteri [66]

From the equation of a line;
y=mx+c
m=2
y=2x+c
Replacing for;
y=1
x=3
1=2*3+c
1=6+c
c=1-6
c=-5
<span>y=2x-5</span>

4 0

3 years ago

Tela A: Compro $/720 de mercancía y le realizaron el 12% de descuento. ¿Cuanto dinero pagó María por la tela A?

Margaret [11]

Answer:

the amount that need to be paid by her is $633.60

Step-by-step explanation:

The computation of the amount that need to be paid by her is shown below:

= Purchase value of merchandise - purchase value fo merchandise × discount rate

= $720 - $720 × 12%

= $720 - $86.4

= $633.60

hence, the amount that need to be paid by her is $633.60

4 0

3 years ago

Compare using <, =, or >. –1.23 _____ –1.25

NARA [144]

Its the arrow that opens to the right

7 0

4 years ago

Read 2 more answers

2. Invasive weed species can grow quickly. One variety grows up to 1.65 ft per day.

Radda [10]

Invasive weed grows at a rate of 0.0011 ft per minute a day

In the above question, it is given as

Invasive weed grows really fast and the rate of its growth is being provided as follows

The rate at which the weed is growing a day is = 1.65 ft

We need to find the, rate at which this weed is growing per minute

So, to do this, we'll find the growth in 1 min

In 24 hours growth is = 1.65 ft

Conversion factors

We know, 1 hour = 60 minutes

In 1 min growth is = $\frac{1.65}{24 . 60}$

Here, we have multiplied with 60 in the denominator to convert hours into minutes

After solving the fraction we'll get

Growth in 1 min of the weed = 0.0011 ft

Hence, Invasive weed grows at a rate of 0.0011 ft per minute a day

To learn more about minute here

brainly.com/question/15600126

#SPJ1

6 0

1 year ago

Suppose that weekly income of migrant workers doing agricultural labor in Florida has a distribution with a mean of $520 and a s

Arada [10]

Answer:

$z = \frac{500-520}{\frac{90}{\sqrt{100}}}= -2.22$

And we can find this probability using the normal standard distribution and we got:

$P(z$

Step-by-step explanation:

For this case we have the foolowing parameters given:

$\mu = 520$ represent the mean

$\sigma =90$ represent the standard deviation

$n = 100$ the sample size selected

And for this case since the sample size is large enough (n>30) we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

And we want to find this probability:

$P(\bar X$

We can use the z score formula given by:

$z = \frac{500-520}{\frac{90}{\sqrt{100}}}= -2.22$

And we can find this probability using the normal standard distribution and we got:

$P(z$

4 0

3 years ago