Answer:
the hotel charge in the first city is $5250 while the hotel charge in the second city is $3750
Step-by-step explanation:
Let a represent the charge in the first city before tax and b represent the charge in the second city before tax.
Therefore tax in first city = 10% of a = 0.1a
Tax in second city = 8% of b = 0.08b
From the total tax as $825, hence:
0.1a + 0.08b = 825 (1)
The hotel charge before tax in the second city was $1500 lower than in the first. This gives the equation:
b = a - 1500
a - b = 1500 (2)
To find a and b, solve equation 1 and 2 simultaneously. Multiply equation 2 by 0.1 and subtract from equation 1:
0.18b = 675
b = $3750
a = b + 1500 = 3750 + 1500 = 5250
a = $5250
Therefore, the hotel charge in the first city is $5250 while the hotel charge in the second city is $3750
