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8_murik_8 [283]
3 years ago
12

1. Jack and Jill purchased a $125,000 house making a 20% down payment and paying the closing

Mathematics
1 answer:
kherson [118]3 years ago
6 0

Answer:

The month payment amount is $897.589

Interest amount is $61,566

Step-by-step explanation:

Given as :

The price of the house = $125,000

The down payment amount for house = 20% of total price

i.e The down payment amount for house = 20% × $125,000

Or, The down payment amount for house = \dfrac{20}{100} × $125,000

Or, The down payment amount for house = $25,000

Now, Balance amount = total price - down payment

Or, Balance amount = $125,000 - $25,000

Or, Balance amount = $100,000

So, The balance amount is bring finance

The finance principal amount = p = $100,000

The rate of interest applied = r = 3.25%

The time period of mortgage = t = 15 years = 15 × 12 = 180 months

Let The Amount of mortgage after 15 years = $A

<u>From Compound Interest method</u>

Amount = Principal × (1+\dfrac{\textrm rate}{100})^{\textrm time}

Or, A = p × (1+\dfrac{\textrm r}{100})^{\textrm t}

Or, A = $100,000 × (1+\dfrac{\textrm 3.25}{100})^{\textrm 15}

Or, A = $100,000 × (1.0325)^{15}

Or, A = $100,000 × 1.61566

Or, A = $161,566

So,The Amount of mortgage after 15 years = $161,566

Interest applied = Amount - principal

Or, I = $161,566 - $100,000

∴ Interest = $61,566

<u>Again</u>

The month payment amount = \dfrac{\textrm amount after 15 years}{number of months of mortgage}

i.e The month payment amount = \dfrac{161566}{180}

Or, The month payment amount = $897.589

Hence The month payment amount is $897.589 and interest amount is $61,566  . Answer

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Step-by-step explanation:

Given that,

f(x, y)=7x−yx+y

We want to show that the limit doesn't exist as (x, y)→(0,0).

Limits typically fail to exist for one of four reasons:

1. The one-sided limits are not equal

2. The function doesn't approach a finite value

3. The function doesn't approach a particular value

4. The x - value is approaching the endpoint of a closed interval

a. Considering the case that y=3x

lim(x,y)→(0,0) 7x−yx+y

Since y=3x

lim(x,3x)→(0,0) 7x−3x(x)+3x

lim(x,3x)→(0,0) 7x−3x(x)+3x

lim(x,3x)→(0,0) 10x−3x²

Therefore,

lim(x,3x)→(0,0) 10x−3x² = 0-0=0

b. Let also consider at y=4x

lim(x,y)→(0,0) 7x−yx+y

Since y=4x

lim(x,4x)→(0,0) 7x−4x(x)+4x

lim(x,4x)→(0,0) 7x−4x(x)+4x

lim(x,4x)→(0,0) 11x−4x²

Therefore,

lim(x,4x)→(0,0) 11x−4x² = 0-0=0

c. Let also consider it generally at y=mx

lim(x,y)→(0,0) 7x−yx+y

Since y=mx

lim(x,mx)→(0,0) 7x−mx(x)+mx

lim(x,mx)→(0,0) 7x−mx(x)+mx

lim(x, mx)→(0,0) (7+m)x−mx²

Therefore,

lim(x, mx)→(0,0) (7+m)x−mx² = 0-0=0

But the limit of the given function exist.

So let me assume the function is wrong and the question meant.

f(x, y)= (7x−y) / (x+y)

So, let analyze again

a. Considering the case that y=3x

lim(x,y)→(0,0) (7x−y)/(x+y)

Since y=3x

lim(x,3x)→(0,0) (7x−3x)/(x+3x)

lim(x,3x)→(0,0) 4x/4x

lim(x,3x)→(0,0) 1

Therefore,

lim(x,3x)→(0,0) 1= 1

So the limit is 1

b. Let also consider at y=4x

lim(x,y)→(0,0) (7x−y)/(x+y)

Since y=4x

lim(x,4x)→(0,0) (7x−4x)/(x+4x)

lim(x,4x)→(0,0) 3x/5x

lim(x,4x)→(0,0) 3/5

Therefore,

lim(x,4x)→(0,0) 3/5 = 3/5

So the limit is 3/5

This show that the limit does not exit.

Since one of the condition given above is met, then the limit does not exist. i.e. The function doesn't approach a particular value

c. Let also consider it generally at y=mx

lim(x,y)→(0,0) (7x−y)/(x+y)

Since y=mx

lim(x,mx)→(0,0) (7x−mx)/(x+mx)

lim(x,mx)→(0,0) (7-m)x/(1+m)x

lim(x, mx)→(0,0) (7-m)/(1+m)

Therefore,

lim(x, mx)→(0,0) (7-m)/(1+m) = (7m)/(1+m)

Then, the limit is (7-m)/(1+m)

So the limit doesn't not have a specific value, it depends on the value of m, so the limit doesn't exist.

7 0
4 years ago
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